Write a c program to reverse a digit 123?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int abcd;

printf("enter a 4-digit no.");

scanf("%d",&abcd);

a=abcd/1000;

abcd=abcd%1000;

b=abcd/100;

abcd=abcd%100;

c=abcd/1o;

abcd=abcd%10;

d=abcd;

printf("reverse=%d",dcba);

getch();

}

Answer 2

Program to reverse ANY given number in C

#include

main()

{

int num,mod,rev=0;

printf("Enter a number:");

scanf("%d", &num);

while(num>0)

{

mod=num%10;

rev=(rev*10)+mod;

num=num/10;

}

printf("Reverse of the given number: %d", rev);

getchar();

}

Other Ideas! Use the While Loop

#include

main()

{

int a,b,c,d,e;

printf("Enter the Number to Find it's Reverse\n");

scanf("%d",&a);

while(a!=0)

{

b=a%10;

c=a/10;

printf("%d",b);

a=c;

}

getchar();

}

Before compiling include stdio.h

-----------------------------------------------------------------------------

Using sprintf/atoi functions./..

int _tmain(int argc, _TCHAR* argv[])

{

int inumber;

printf("\n\n Enter a Number:");

scanf("%d",&inumber);

char pNumber[10];

sprintf(pNumber, "%d", inumber);

int iLength=strlen(pNumber);

char temp;

for(int i=0;i

temp=pNumber[i];

pNumber[i]=pNumber[iLength-1];

pNumber[iLength-1]=temp;

iLength--;

}

inumber=atoi(pNumber);

printf("\n\nReverse no is %d",inumber);

getchar();

return 0;

}

Answer 3

h = x/100; // (1) x = 325, h = 3 (2) x = 1, h = 0

u = x%10; // (1) u = 5 (2) u = 1

y = x - 99* (h - u); // (1) y = 325 - (-198) = 523 (2) y = 1 - (-99) = 100

OK? Comments show two examples, 325 to 523 and 1 to 100.

h=num%100 u=h%10

g=num/100

i=h/10

numreverse=u*100+i*10+g

Answer 4

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b;

printf("Enter number:\t);

scanf("%d",a);

printf("Reversal of number: ");

do {

b=a%10;

printf("%d",b);

a = a/10;

} while(a>0);

getch();

}

Answer 5

//Reverse of the Number

// Programme Written By Maulin Thaker Ahmedabad;

#include

#include

void main()

{

int a,b,c,d,e;

clrscr();

printf("Enter the Number to Find it's Reverse\n");

scanf("%d",&a);

while(a!=0)

{

b=a%10;

c=a/10;

printf("%d",b);

a=c;

}

getch();

}

Answer 6

#include<stdio.h>

#include<conio.h>

void main()

{

int n,a,b;

long int revnum=0;

clrscr();

printf("\n Enter three digit number");

scanf("%d", &n);

a=n%10;

n=n/10;

revnum=revnum+a*100;

a=n%10;

n=n/10;

revnum=revnum+a*10;

a=n%10;

revnum=revnum+a;

printf("\nThe reversed number is %ld",revnum);

getch();

}

Answer 7

#include<srdio.h>

#include<conio.h>

void main()

{

int num,reverse;

clrscr();

printf("enter any number ==>")

scanf("%d",&num);

reverse=rev(num);

printf("reverse of number is==>%d",reverse);

getch();

}

int rev(int num)

{

static sum,r;

if(num)

{

r=num%10;

sum=sum*10+r;

rev(num%10);

}

else

return 0;

return sum;

}

Answer 8

#include<stdio.h>

#include<conio.h>

int main (void)

{

int n,s=0,d;

clrscr();

printf("\n Enter the no. which u want to reverse\n");

scanf("%d",&n);

while(n>0)

{

d=n%10;

s=s*10+d;

n=n/10;

}

printf("\nThe reverse no. is=%d",s);

getch();

return 0;

}

Answer 9

int RevNum( int num )

{

const int base = 10;

int result = 0;

int remain = 0;

do

{

remain = num % base;

result *= base;

result += remain;

} while( num /= base);

return( result );

}

int main()

{

int n;

printf( "Enter a value:\t" );

scanf( "%d", &n );

printf( "Reversed:\t%d\n", RevNum( n ));

}