Remember in linear mode there 12 inches in 1 foot.
Hence in area mode there are 12 ins. x 12 ins = 144 sq.ins. in 1 sq.ft.
Length is 6.3 ft and width is 2.5 ft.
Hence Area is 6.3 ft X 2.5 ft = 15.75 sq.ft.
Multiply by 144 to find the number of square inches.,
Hence
15.75 sq.ft. X 144 = 2268 sq.ins. (square inches)
NB In the Imperial system of linear/square/cubic measure, it is ins./sq.ins/cu.ins. respectively. NEITHER ins^2 nor ins^3
NNB Another way to do this is to convert the linear measurements to inches, by multiplying each length by 12' . Then multiplying the two answer.
Hence 6.3 x 12 = 75.6 ins
2.5 X 12 = 30 ins
Then multiplying 75.6 ins X 30 ins = 2268 sq.ins. (As before)
NNNB Be careful when multiplying the decimals. The decimals are NOT the same measurement as 'inches'.
we know that area of rectangle is given as =l X b.
1 feet =12 inches .
thus ,3 feet =12 X3 and 4 feet =12 X4 inches .
so, area here = 3 X 12 X 2 x12.
thus,area =864 inch 2
how many inches are around aectangle that is 3 feet long and 2 feet wide
2268 in
2
1 foot = 12 inches. So, 26.3 feet = 26.3 x 12 = 315.6 inches.
22 feet is 6.71 metres, 9 inches is 0.23 metres. 22 feet and 9 inches is 6.94 metres.
it is 12 inches. 3 feet is a yard.it's about the length of 2 dollar bills.A foot (plural: feet) is 12 inches or about 30 cm.
5.1 meters is 16 feet and 8.79 inches.
9 meters is 29 feet and 6.33 inches.
26 feet.
44 feet 4 inches
3 feet + 2 feet + 3 feet + 2 feet = 10 feet. It really is very simple!
26 feet
If the length is 15.5 feet then the combined length of the two long sides is 31 feet, this leaves 9 feet, which divided between the two shorter sides means each must be 4.5 feet long or 4 feet 6 inches long if you prefer.
The perimeter is 10 feet. P = 2L + 2W P = 2(3) + 2(2) = 6 + 4 = 10
If the area is a rectangle then the perimeter in feet is: 2.5+7+2.5+7 = 19 feet, since 84 inches is the same as 7 feet.
The square footage of a rectangle with dimensions 233 inches by 144 inches is 223 ft2.
The perimeter is 33 feet 2 inches
3 sq. ft. or 432 sq. in.
Seven 9 inch squares placed end to end would form a rectangle that was still 9 inches wide but 7 x 9 = 63 inches long. The distance around such a rectangle would measure its perimeter. Two sides are 9 inches long and two sides are 63 inches long. The perimeter would be 63 + 63 + 9 + 9 = 144 inches.
The area of rectangle is : 150.0