What does a B and a f average out to
a a a a a d c g a b a a a a a d c g a b c d e g a d e b a d
A a a a g g g a a g g f e a a a a g g a a a a g g f f f e d b b c c c d d d c b c d e f g a b b a g g f f g g b a a b b a b b a g f f b b a b b a g g f f g g b a a b b a f f e e d d d c b a b a a b b a f f e e d d
F A B, F A B, F A B E D B C B A E F A B, F A B, F A B E D Unfortunately this is all I have. Hope this helped.
My heart is pierced by cupid - A B C E E F I disdain all glittering gold - C B A A B B C There is nothing can console me - A B C A A F F E But my jolly sailor bold - E E A G(minor) B G(minor) A
F# e d e f# f# f# e e e f# a a f# e d e f# f# f# f# e e f# e d
If it's the average speed of [a,b] where a is less than b, both are on the x axis (time), and both are in the domain of x then the equation is(f(b)-f(a))/(b-a)where f(b) is the distance when time=b and f(a) is the distance when time=a(?)
it will be a B.
The average value of a function is the equivalent area of the function expressed like a rectangle .- Thus If you have an area A from limits a and b , the equivalent is : (b-a) H ( rectangle area ) = INT f(x) dx , then average H is H= ( INT f(x) dx) /(b-a)
To find the average rate of change of a function ( f(x) ) over the interval ([a, b]), you use the formula (\frac{f(b) - f(a)}{b - a}). In your case, since the interval is given as "413," I'm assuming you meant the interval ([4, 13]). You would need the values of ( f(4) ) and ( f(13) ) to calculate this average rate of change. Once you have those values, simply plug them into the formula to find the result.
a a a a a d c g a b a a a a a d c g a b c d e g a d e b a d
#include<stdio.h> #include<conio.h> voidmain() { char n[10] ,total; float a,b,c,d,e,average; printf("enter marks of five subject"); scanf("%f%f%f%f%f",&a,&b,&c,&d,&e); if(a>35&&b>35&&c>35&&d>35&&e>35) printf("congratulation you have passed"); average=total%5 if(average>75) printf(" %f is distictiona",average); else if(average>60) printf("%f=first devision",average); else if(averagea>45) printf("%f=second devision",average); else printf("third devisiona"); getcha(); }
A a a a g g g a a g g f e a a a a g g a a a a g g f f f e d b b c c c d d d c b c d e f g a b b a g g f f g g b a a b b a b b a g f f b b a b b a g g f f g g b a a b b a f f e e d d d c b a b a a b b a f f e e d d
/*mycfiles.wordpress.com To Calculate Sum & Average of 4 no.*/ #include<stdio.h> #include<conio.h> void main() { float a,b,c,d,sum,avg; clrscr(); printf("Enter the 4 nos.\n\n"); scanf("%f%f%f%f",&a,&b,&c,&d); sum=a+b+c+d; avg=(a+b+c+d)/4; printf("\nSum is= %f\nAverage is= %f",sum,avg); getch(); }
a*f(b)-b*f(a)/f(b)-f(a).........
F A B, F A B, F A B E D B C B A E F A B, F A B, F A B E D Unfortunately this is all I have. Hope this helped.
My heart is pierced by cupid - A B C E E F I disdain all glittering gold - C B A A B B C There is nothing can console me - A B C A A F F E But my jolly sailor bold - E E A G(minor) B G(minor) A
The average rate of change of a function between two points ( x = a ) and ( x = b ) is calculated using the formula ( \frac{f(b) - f(a)}{b - a} ). In this case, if we consider ( f(x) ) as a linear function, the average rate of change from ( x = 5 ) to ( x = 1 ) can be expressed as ( \frac{f(1) - f(5)}{1 - 5} ). This results in a negative average rate of change, reflecting the decrease in the function's values as ( x ) moves from 5 to 1. To compute a specific rate, the actual function ( f(x) ) must be known.