No. Electrons are fermions, meaning they cannot share the same set of four quantum numbers. Usually when we say "orbital" we only mean the first three, so there is room for two electrons in an orbital (corresponding to the two possible ms values).
False. Only two electrons with opposite spins can occupy an orbital.
No - only two electrons with opposite spin can occupy the same orbital
3
Lead has 82 electrons. It also has four valence electrons, two s- electrons and two p- electrons in its orbitals.
Every orbital is different. 2 can occupy the first orbital then 8 can occupy mostly the rest. When you start getting really low on the periodic table orbitals start holding 16, but not till u get really low
There are 6 Chlorine has 7 valence electrons, and since 2 of them can occupy one s orbital, there needs to be 5 p orbitals for everything else. (5+1=6)
Arsenic has three electrons occupying the three 4p orbitals in its valence shell. Hund's first rule tells us that they will each occupy separate orbitals before they start to pair up. So there are three half-filled orbitals in an arsenic atom.
for the case of n=4 the available orbitals include 1s 3p and 5d, a total of 9 electron orbitals which can occupy 18 electrons. There are 18 elements in the 4th row which coincides with the 9 available orbitals.
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26 sigma 7 pi
5 electrons in p orbitals in the outer shell. Cl has an electronic configuration of [Ne] 3s2, 3p5 In level 2 there a further 6 electrons in p orbitals making 11 electrons in total occupying p orbitals
two and both must be of opposite spin to each other
In theory all elements have all the orbitals. Zinc has electrons in four of them.
Lead has 82 electrons. It also has four valence electrons, two s- electrons and two p- electrons in its orbitals.
Every orbital is different. 2 can occupy the first orbital then 8 can occupy mostly the rest. When you start getting really low on the periodic table orbitals start holding 16, but not till u get really low
There are 6 Chlorine has 7 valence electrons, and since 2 of them can occupy one s orbital, there needs to be 5 p orbitals for everything else. (5+1=6)
17. The electronic configuration of bromine is 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 4p5
Two electrons can occupy the 2s subshell, and 8 electrons can occupy the 3d subshell.
Arsenic has three electrons occupying the three 4p orbitals in its valence shell. Hund's first rule tells us that they will each occupy separate orbitals before they start to pair up. So there are three half-filled orbitals in an arsenic atom.
for the case of n=4 the available orbitals include 1s 3p and 5d, a total of 9 electron orbitals which can occupy 18 electrons. There are 18 elements in the 4th row which coincides with the 9 available orbitals.