Using the Electrical Power Law, which is:
The current (measured in amps) equals the power (measured in watts) divided by the potential difference (measured in volts)
So a light bulb designed to use 60 watts of power when supplied with 120 volts must draw 60 watts divided by 120 volts, which is a current of 0.5 amps.
The same answer could be expressed in a few different ways:
On a 240 v supply, ¼ amp. On a 120 v supply, ½ amp. On a 12 v supply, 5 amps. In each case the light must be correct for the supply voltage used.
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The equation used to find this answer is I = W/E, Amps = Watts/Volts.
As the question appears above, there is no answer.
If the question was intended to say "... 120 volts...", then the light bulb draws 1/2 Ampere of current.
Assuming that the bulb is a 120 Volt rated bulb, I=P/E=60/120=.5 Amps. Where I=current, P=Watts, and E=Volts
60 watts divided by 120 volts = 0.5 Amps
0.5 Amps of current
The formula you are looking for is I = W/E. Amps = Watts/Volts.
.5 Amps.
.5amps
Let R be the resistance, V the voltage, and I the current R = V / I R = 120 / 24 R = 5 ohm
600 VDC.
Use Ohm's Law, i.e., V=IR here, V=voltage I=current R=resistance
you divide the volts by the ohms
The formula you are looking for is I = W/E. Amps = Watts/Volts.
Ohm's Law Volts = Current x Resistance Amps = V / R 110 / 20 = 5.5 Amps
4 amps
Ohm's Law Voltage = Current x Resistance Answer is 15/300
Assuming that you mean connected to 120 Volts (V) supply, start with Power(P)=Current(I) x Voltage(V), and if P=V*I, then I=P/V. I=12W/120V=0.1A or 100mA and that is your current.
Ohms are the unit of resistance you find in Ohms LAw which says Volts = Amps x Ohms. You can get a voltage drop across a resistance, but would have to know what current is being used and you would have a potentiometer in effect. You are not "converting 12V" to 10V, your are essentially loosing two volts through a resistor.
That depends on the voltage which the current flows through. I = P / U I = 1500 / U Where I is the current in Amperes and U is the effective voltage in Volts. (P is the power)
Let R be the resistance, V the voltage, and I the current R = V / I R = 120 / 24 R = 5 ohm
The three electrical quantities are current voltage and resistance. Current is measured in amperes (A) and is the rate at which electricity flows through a conductor. Voltage is measured in volts (V) and is the electrical force pushing the current through the conductor. Resistance is measured in ohms () and is the opposition to the flow of current. Current - measured in amperes (A) Voltage - measured in volts (V) Resistance - measured in ohms ()
600 VDC.
120 power flows through a circuit with 1 amp and 120 volts.
-10
V = (I) x (R) = 2 x 12 = 24 volts