How many inches are around a rectangle 3 feet long and 2 feet wide?

Answer 1

Remember in linear mode there 12 inches in 1 foot.

Hence in area mode there are 12 ins. x 12 ins = 144 sq.ins. in 1 sq.ft.

Length is 6.3 ft and width is 2.5 ft.

Hence Area is 6.3 ft X 2.5 ft = 15.75 sq.ft.

Multiply by 144 to find the number of square inches.,

Hence

15.75 sq.ft. X 144 = 2268 sq.ins. (square inches)

NB In the Imperial system of linear/square/cubic measure, it is ins./sq.ins/cu.ins. respectively. NEITHER ins^2 nor ins^3

NNB Another way to do this is to convert the linear measurements to inches, by multiplying each length by 12' . Then multiplying the two answer.

Hence 6.3 x 12 = 75.6 ins

2.5 X 12 = 30 ins

Then multiplying 75.6 ins X 30 ins = 2268 sq.ins. (As before)

NNNB Be careful when multiplying the decimals. The decimals are NOT the same measurement as 'inches'.

Answer 2

we know that area of rectangle is given as =l X b.

1 feet =12 inches .

thus ,3 feet =12 X3 and 4 feet =12 X4 inches .

so, area here = 3 X 12 X 2 x12.

thus,area =864 inch 2

Answer 3

how many inches are around aectangle that is 3 feet long and 2 feet wide

Answer 4

The perimeter of the rectangle would be 10 feet (3 feet + 3 feet + 2 feet + 2 feet) which is equal to 120 inches (10 feet x 12 inches/foot).

Answer 5

2268 in

2