2520 Joules = (X)(4.180J/gC)(30C-10C)
2520J = 83.6X
30.14 grams of water.
q(Joules) = mass * specific heat * change in temp.
q = (200 grams)(4.180 J/gC)(40.0 C - 10.0 )
= 2.51 X 10^4 Joules
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q(Joules) = mass * specific heat * change in temperature.
q = (15 grams)(4.180 J/gC)(40 C - 30 C)
= 627 Joules
-----------------------( call it 630 Joules )
The answer is 1256 joules.
do your hw
150*10*4.18
5
42j
Released
Released
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Released
Released
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