chromium (III) acetate
at least this is what masteing chemistry told me after I guessed wrong three times I however am not to sure because my chem. teacher "doctor" Ott did not bother teaching me how to figure this out before she assigned it for homewor
Cr+3 C2H3O2-1 <----- these are the ions and their charges Cr+3 C2H3O2-1 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so three -1 acetate ions cancel out one +3 chromium ion Cr(C2H3O2)3 <----- simplify
The chemical formula for chromic acetate is Cr(C2H3O2)3.
The formula for boron acetate is B(C2H3O2)3.
The formula for erbium acetate is Er(C2H3O2)3.
CrNO3 ************2nd Opinion*********** To get the correct formula, you need to state the oxidation number of chromium in the compound, using a Roman numeral. It's likely to be chromium(III) nitrate, which is Cr(NO3)3
Cr+3 C2H3O2-1 <----- these are the ions and their charges Cr+3 C2H3O2-1 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so three -1 acetate ions cancel out one +3 chromium ion Cr(C2H3O2)3 <----- simplify
The chemical formula for chromic acetate is Cr(C2H3O2)3.
3 +
The formula for boron acetate is B(C2H3O2)3.
The formula for erbium acetate is Er(C2H3O2)3.
Fe(C2H3O2)3.
Assuming that the questioner meant the formula to be Al(C2H3O2)3, which the questioner probably was unable to write on a normal keyboard, the answer is aluminum acetate.
Al(C2H3O2)3 - first, aluminium is in the beginning of the equation and acetate needs to be after. Aluminium has a charge of +3 making it Al+3 -acetate has a charge of -1 and its formula is C2H3O2- Using the crossover method, we see that it would take three acetate ions (-1 charge) to balance out the 1 Aluminium Ion (+3 charge). So the final equation should be Al(C2H3O2)3
CrNO3 ************2nd Opinion*********** To get the correct formula, you need to state the oxidation number of chromium in the compound, using a Roman numeral. It's likely to be chromium(III) nitrate, which is Cr(NO3)3
The chemical formula for aluminum ethanoate is Al(C2H3O2)3.
Al(CH3COO)3
The formula for chromium(III) bicarbonate is Cr(HCO3)3.