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There are 5 total 4 d orbitals. (4dy, 4dx, 4dz, 4dz2, 4dx2-y2) Each of these can fit 2 electrons. This rule is known as the Pauli Exclusion Principal. 2X5 = 10. 10 total electrons. This is the same for all d orbitals. 1d, 2d, 3d, 4d, 5d, etc.
Wiki User
∙ 13y ago
Wiki User
∙ 13y agoThe answer is 14, if you go to where Ce is on the Periodic Table and count over to the right across the whole row, there is a total of 14 elements that could fit into the 4f orbital
Wiki User
∙ 11y agoAny s orbital can only hold 2 electrons maximum.
Wiki User
∙ 14y ago10 electrons
Chirag Gupta
Chirag Gupta
10 electrons
CG'S CHEMISTRY SOLUTIONS
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What are the valence electrons for Sb?
Long-hand version: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^3 Short-hand version: [Kr] 5s^2 4d^10 5p^3 Note: The "^" symbol means the the following number is in the form of a superscript.
What is the noble gas notation for zirconium?
1s with two arrows, 2s with 2 arrows, 2p with 6 arrows, 3s with 2 arrows, 3p with 6 arrows, 4s with 2 arrows, 3d with 10 arrow; Remember that orbital notation uses arrows, and electron-configuration notation uses superscripts.
What is the wavelength of light emitted during a transition from the 4d orbital to the 2p orbital in Lithium?
Two step process. First this formula finding period, which is Hertz. (s -1)( Z number lithium = 3 )Hertz = (3.29 X 1015 s -1)*(Z2)*[1/Nf2 - 1/Ni2]Hertz = (3.29 X 1015 s -1)*(32)*[1/22 - 1/42]Hertz = (3.29 X 1015 s -1)*(9)*(1/4 - 1/16)= 5.55 X 1015 Hertz------------------------------now,Wavelength = speed of light/HertzWavelength = 2.998 X 108 (m/s)/5.55 X 1015 Hertz (s -1)= 5.40 X 10 -8 meters================== ( 54 nanometers ????? Seems unreasonable, but the formulas and work check )
What the electron configuration of iodine?
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6
What is the orbital notation for silicon?
You'll find that [Kr] 5s24d9 is the noble gas notation for silver, with Kr being krypton.
What is the maximum number of electrons that can occupy the n equals 4 energy level?
there are 16 orbitals in a n=4 shell *since there are 2 electrons in each orbital, that makes 32 electrons total here
What is the orbital of the element yttrium?
The valence electrons fill in 4d orbital The electron configuration of yttrium is [Kr]4d15s2.
What is the maximum number of electrons each of the following can hold... 2s 5p 4f 3d 4d?
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
Which orbital is rhodium's last electron in?
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
How many electrons can be acomodated in a 5d orbital?
The d sublevel always contains 5 orbitals. Therefore the d sublevel can accommodate 10 electrons just the same as 3d and 4d orbitals. Each of the 5 separate d orbitals can only contain two electrons.
What is the maximum number of electron found in the fourth main shell of an atom?
Use the formula n2 = max. number of electrons in shell. 42 = 16. 16 electrons.
What is the number of 4d electrons in Mo?
5
Why does one electron in a rubidium atom occupy a 5s orbital rather than a 4d or 4f orbital?
in 5s it is filled but in 4d or 4s its half
How many orbitals are in the 4d subshell?
One orbital - 6s which can hold 2 electrons.
How many electrons are there in the 3s orbital?
Yes, it exists. If you write the orbitals in order of increasing energy, then you get it. The order is:- 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p..................... Here, you get the 3s orbital at the 4th place.
How would the 4d orbitals differ from the 3d orbitals?
The 4d orbital would be the same shape as the 3d orbital, but just a larger size. Also it would have more nodes than he 3d orbital.
What element has three 4d electrons?
Niobium (Nb) Because three 4d electrons = 3d^3
