CH3OH, or methanol, is an organic compound. It is also known as wood alcohol and is both highly flammable and toxic.
No, CH3OH is not an element. It is a compound with the chemical formula CH3OH, which represents methanol, a type of alcohol.
--> number of moles of CH3OH = mass/molar mass 22/(12+3+16+1) = 0.6875 moles --> number of mole = conc multiply by volume(indm3) number of moles divided by volume[indm3] = concentration 0.6875/[.25] = 2.75 mol/dm3
Methanol is CH3OH while ethanol is C2H5OH. The difference is CH2.
CH3OH is an alcohol, in particular methyl alcohol or methanol. The OH is the alcohol functional group.
The molarity of methanol (CH3OH) and ethanol (C2H5OH) depends on the concentration of each substance in a given solution. To calculate the molarity, you need to know the amount of the solute (methanol or ethanol) in moles and the volume of the solution in liters. The formula for molarity is moles of solute divided by liters of solution.
Methanol and water do not react they just form a very stable solution.
The van't Hoff factor for CH3OH (methanol) is 1, since it does not dissociate into ions in solution.
NONE of them. CH3OH is an organic alcohol ( Methanol). However, in suitable circumstances it will react with an acid to form as ester.
It is CH3OH
Methanol is CH3OH, and contains carbon. hydrogen, and oxygen.
No, CH3OH (methanol) is not an Arrhenius base. It is a weak acid.
CH3OH, or methanol, is an organic compound. It is also known as wood alcohol and is both highly flammable and toxic.
No, CH3OH is not an element. It is a compound with the chemical formula CH3OH, which represents methanol, a type of alcohol.
The definition of a strong acid relatively is the stability of the conjugate base after deprotonation. The equilibruim lies far to the right of methanol (CH3OH). CH3OH2+== CH3OH
Methanol is an alcohol and consists of carbon,hydrogen and oxygen its formula is CH3OH
--> number of moles of CH3OH = mass/molar mass 22/(12+3+16+1) = 0.6875 moles --> number of mole = conc multiply by volume(indm3) number of moles divided by volume[indm3] = concentration 0.6875/[.25] = 2.75 mol/dm3