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In the reaction Mg(s) plus 2H2O(I) and 61664 Mg(OH)2(s) plus H2(g) what is the oxidation state of each H in H2(g)?

Updated: 8/11/2023

Wiki User

∙ 7y ago

Best Answer

Simply remember OIL RIG. Oxidation Is Loss (of electron) and Reduction Is Gain (of electron). In the case of MnO4-(aq) + 8H+(aq) + 5e- --> Mn2+(aq) + 4H2O(l) H is the oxidizing agent, because it causes Mn to be oxidized to Mn2+.

Wiki User

∙ 9y ago

This answer is:

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Wiki User

∙ 6y ago

The oxidation state of magnesium in magnesium hydroxide is +2 no matter what reaction you are looking at.

This answer is:

Maryam G. ∙

Lvl 1

∙ 2y ago

correct!

pervy toad ∙

Lvl 1

∙ 1y ago

I got wrong it's 0

Priscus Didas ∙

Lvl 1

∙ 1y ago

This answer is correct

Wiki User

∙ 14y ago

The Chlorine. Which is being reduced ( accepting electrons )

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Haven ∙

Lvl 7

∙ 1y ago

0

This is the answer on Apex, +2 is wrong

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Jesus H ∙

Lvl 1

∙ 11mo ago

Correct on CST 5.5.2 chemistry 1

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Q: In the reaction Mg(s) plus 2H2O(I) and 61664 Mg(OH)2(s) plus H2(g) what is the oxidation state of each H in H2(g)?

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In the reaction Mg(s) plus 2H2O(I) and 61664 Mg(OH)2(s) plus H2(g) what is the oxidation state of each H in H2(g)?

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