A certain system absorbs 350joules of heart and has 230joules of work done on it. What is the value of Delta?
The internal energy change of the system would be the sum of the heat absorbed and the work done on the system. Therefore, the internal energy change would be 20000 J (heat absorbed) + 5000 J (work done) = 25000 J.
400 joules.
The work done by the system can be calculated by finding the difference between the heat absorbed from the high-temperature reservoir and the heat passed onto the low-temperature reservoir. In this case, the work done by the system is 130 joules (425 joules - 295 joules).
1,000 J
The work done by the system can be calculated using the formula: Work = Force × Distance × cos(θ). Since work is given as -2.37 kJ, we convert this value to joules (1 kJ = 1000 J). So, the work done is -2.37 kJ × 1000 J/kJ = -2370 J. Therefore, the work done by the system when it absorbs 650 J of energy during a change is -2370 J + 650 J = -1720 J or -1.72 kJ.
The internal energy change of the system would be the sum of the heat absorbed and the work done on the system. Therefore, the internal energy change would be 20000 J (heat absorbed) + 5000 J (work done) = 25000 J.
400 joules.
The work done by the system can be calculated by finding the difference between the heat absorbed from the high-temperature reservoir and the heat passed onto the low-temperature reservoir. In this case, the work done by the system is 130 joules (425 joules - 295 joules).
1,000 J
The work done by the system can be calculated using the formula: Work = Force × Distance × cos(θ). Since work is given as -2.37 kJ, we convert this value to joules (1 kJ = 1000 J). So, the work done is -2.37 kJ × 1000 J/kJ = -2370 J. Therefore, the work done by the system when it absorbs 650 J of energy during a change is -2370 J + 650 J = -1720 J or -1.72 kJ.
The dimension for work done is energy, which has units of joules (J) in the International System of Units (SI).
To calculate the work done by the system, we can use the formula for efficiency: Efficiency = Work output / Heat input. First, let's determine how much heat is not passed on to the lower temperature reservoir: 425 - 295 = 130 J. Thus, the work done by the system is the heat that is not passed on, which is 130 joules.
The change in internal energy of a system that does 100 joules of work depends on the heat exchange as well. In general, the change in internal energy is equal to the amount of heat added to the system minus the work done by the system.
The units for work done are joules (J) in the International System of Units (SI). Another common unit for work is the erg in the centimeter-gram-second system.
Yes, because power is a measure of how quickly work is done. In this case, the power for the 200 joules of work done in 20 seconds would be 10 watts, while the power for the 50 joules of work done would be 2.5 watts. Hence, 200 joules of work done involves more power than 50 joules of work done.
Various forms of energy can be measured in joules, such as kinetic energy, potential energy, heat energy, and electrical energy. Joules are a unit of measurement for energy and can be used to quantify the amount of energy present in a system or the amount of work done.
Joules are a unit of measurement for energy in the International System of Units (SI). It is used to quantify the energy transferred, work done, or heat produced in various scientific contexts such as physics and chemistry. It is equivalent to the work done by a force of one newton acting over a distance of one meter.