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The object accelerates at 9.8 meters per second per second (9.8 m/s2), so for each second of free fall, its speed increases 9.8 m/s. So, the final velocity after five seconds is 5 x 9.8 = 49 m/s.

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11y ago
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Anonymous

Lvl 1
3y ago
no 
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Anonymous

Lvl 1
3y ago
cause in my test its that exact question but deosnt give that anserc hoice 
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Wiki User

13y ago

Acceleration of gravity = 9.8 meters (32.2 feet) per second2

Speed = initial speed plus (acceleration x time) =

58.8 meters (192.9 feet) per second.

(Ignoring air resistance, and rounded.)

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Wiki User

8y ago

Any free falling object has only one force causing its acceleration, gravity. Gravity will cause consistent acceleration forever, whether its 5 seconds, 6 seconds or 1000000 seconds. That acceleration, on earth, is 9.8 m/s^2.

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11y ago

The same as in the first second. Near Earth, this is about 9.8 m/s2.

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14y ago

Assuming that the object was dropped on our planet, somewhere near sea level, the velocity after 5s of free fall will be 160 feet/sec, downwards.

(air resistance being neglected)

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14y ago

Using the formula: v=v0+a*t. v = ?, v0 = 0, a = 10, t = 5.

v = 50m/s.

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Q: For a freely falling object dropped front rest what is the acceleration at the end of the fifth second of the fall?
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