The distance between two objects increases the force of gravity becomes what?

Answer 1

As their mass does not change their gravitational force remains the same. For them to move closer together one of the objects must have a stronger gravitaional force than the other. If they collided and became fused together then the gravitaional force would be greater as there would now only be one object.

Answer 2

As the distance between two objects increases, the force of gravity between them decreases. This relationship is described by the inverse square law, which states that the force of gravity is inversely proportional to the square of the distance between the objects. Therefore, the force of gravity becomes weaker as the distance between two objects increases.

Answer 3

It's 1/9 as strong. The reason is the gravitational force between two objects is a function of the distance between them squared. The universal law of gravity defines the force F between two masses as:

F = G * (m1*m2) / r^2

where G is the gravitational constant, 6.672e-11, m1 and m2 are the masses of the two objects, and r is the distance between them.

When you triple the distance, imagine r is replaced by 3r. The denominator becomes (3r)^2, which equals 9 * r^2. Hence the force is one ninth that of the original case.

Answer 4

When you look at the formula for the gravitational force, you see that the masses

are in the numerator of the fraction, and the square of the distance is in the

denominator. This tells you that greater distance produces less force, and that

the force falls off as fast as the square of the distance rises.

So if the distance is multiplied by 4, the force is multiplied by 1/(4)2 = 1/16 .

The force becomes 1/16 of what it was, or 61/4 % .

Answer 5

No. That would be a disaster.
Imagine what the gravitational force would be between you and a star on the other side of the galaxy !

It's just the opposite: As the distance between objects increases, the gravitational force between them DECREASES.
And it decreases a lot faster than you might expect: It falls off as the SQUARE of the distance.

That means if you push two objects 'X' times farther apart, the force between them is not '1/X', it's '1/X2'.
That's a big difference:
If you push two objects 5 times farther apart, the force doesn't shrink to [ 1/5th = 20 percent ].
It shrinks to [ 1/25th = 4 percent ].

If the objects move to 100 times farther apart, the gravitational force drops to 1/10,000th.

Answer 6

Gravitational attraction is known as an "inverse square" force. Its magnitude is proportional to 1/(distance between the masses)2. If the distance between two masses is tripled, the gravitational attraction between them becomes 1/32 = 1/9 of its original magnitude.

Answer 7

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them, so, if the distance is decreased by a factor of 3, then the force would increase by a factor of 9.

Answer 8

Ooops! You were going along pretty good there, but then you stubbed your toe.

As it stands, the "question" is a false statement. It can become a true statement

if the word "volume" is replaced by the word "mass".

Answer 9

When the mass of either object or both objects increases, the gravitational force

of attraction between them increases.

When the distance between the centers of the two objects increases, the gravitational

force of attraction between them decreases.

Answer 10

No, that reduces it to one quarter, not to half.

In the equation for gravitational force (F=G(m1m2/r2) the distance is squared, so doubling the r (2r2) results in the two in front of the r also being squared, resulting in 1/4 the force. This is the same for electrical force which is a similar equation ( F=K(q1q2/r2). Likewise, halving the distance quadruples the force, it does not double the force.