For this question the exact formula has to be known, distinguishing the four different chloromethanes: mono-, di-, tri- and tetra- chloromethane, in which equal H atoms are substituted by Cl atoms around the (one) centered C atom.
p= number of protons, n= number of neutrons, e= number of electrons
Then add up pro atom p / n / e / values for one of these compounds
Example:
CH3Cl : 26p, 24.45n, 26e in monochloromethane (methylchloride)
7 protons, 7 neutrons and 7 electrons
4 protons, 4 electrons and 6 neutrons.
it has 44 electrons 57 neutrons and 44 protons
Sodium has 11 protons, 11 electrons and 12 neutrons.
The phosphorus atom has 15 protons and electrons and 16 neutrons.
18 protons 18 electrons 22 neutrons
18 protons and electrons and 22 neutrons.
Cesium has 55 protons, 78 neutrons, and 55 electrons.
61 neutrons 10 electrons 46 protons
There are 19 protons,20 neutrons, and 19 electrons.
7 protons, 7 neutrons and 7 electrons
50 electrons, 50 protons and 56 neutrons.
67 protons, 67 electrons and 98 neutrons
4 protons, 4 electrons and 6 neutrons.
Neutrons: 58 Electrons: 45 Protons: 45
4 protons, 4 electrons and 5 neutrons
it has 44 electrons 57 neutrons and 44 protons