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For this question the exact formula has to be known, distinguishing the four different chloromethanes: mono-, di-, tri- and tetra- chloromethane, in which equal H atoms are substituted by Cl atoms around the (one) centered C atom.

p= number of protons, n= number of neutrons, e= number of electrons

  • per C atom: 6p, 6n, 6e
  • per H atom: 1p, 0n, 1e
  • per Cl atom: 17p, (18n or 20n)= average 18.45n, 17e

Then add up pro atom p / n / e / values for one of these compounds

Example:

CH3Cl : 26p, 24.45n, 26e in monochloromethane (methylchloride)

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15y ago

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