How much work is it to lift a 20kg sack of potatoes vertically 6.5 m?

Answer 1

in ur case force is weight

so :

work= (m*g) *d

work= [20kg* 9.81m/s^2 ] *6.5m

work= 1275.3 Joules (or J)

Answer 2

That depends on the mass of the sack of rice, which isn't given in the question.

(But it doesn't depend on the time taken to perform the lift, which is given.)

Answer 3

Work = (weight) x (height raised) = (mass) x (gravity) x (height) =

(20) x (9.8) x (6.5) = 1,274 newton-meters = 1,274 joules

or 940.29 foot-pounds (rounded)

Answer 4

The work done in lifting the sack of potatoes vertically can be calculated using the formula: work = force x distance x cos(theta), where force = weight x gravity. So in this case, the work done would be 20 kg x 9.8 m/s^2 x 6.5 m = 1274 J.

Answer 5

You would have to lift 1 meter every 5 seconds because 25 seconds divided by 5 meters is 5 seconds every 1 meter so it would be almost no work

Answer 6

Work = m g h

So 20 * 9.8 * 6.5

Could be simplified. Unit is joule

Answer 7

Use the formula for potential energy: PE = mgh (mass x gravity x height). If the mass is in kilograms, the height in meters, and you use 9.8 m/s2 for gravity, the answer will be in Joule.