The volume of a cylinder (with a radius of r and a length L ) in the horizontal position filled to a depth (d) can be calculated with the following formula:
L((r2)*(arcos((r-d)/r)) - (r-d)*sqrt(2rd-d2))
Note: Calculator must be set to work in radians as opposed to degrees
The buoyant force on an object is equal to the weight of the fluid displaced by the object. To calculate the buoyant force on the 446 gram cylinder, you need to know the density of the fluid it's submerged in and the volume of the cylinder. Using the formula Buoyant force = Density of fluid x Volume of object x gravitational acceleration, you can find the buoyant force acting on the cylinder.
The volume of a cylindrical container is dependent on the container's dimensions. Here is the formula for Volume of a cylinder. Volume = π * R2 * H Where r Is the radius of the circular end of the container, and H is the height of the container.
Yes, energy as work can be transferred to an incompressible fluid in an insulated cylinder fitted with a frictionless piston. This is because the fluid is incompressible, so the volume does not change as the piston moves. It allows work to be transferred to the fluid without any change in pressure or volume.
Horizontal buoyancy refers to the force exerted by a fluid on an object that causes it to move horizontally, typically in a direction perpendicular to the force. This force is determined by the object's shape, volume, and the density of the fluid. Horizontal buoyancy plays a role in determining the stability and motion of objects floating or submerged in fluids.
The method you would use is to take a graduated cylinder, face the markings towards you, fill the cylinder with a liquid that won't react with said object (usually water is fine) to an appropriate measure (around half way depending on the size of the object), record the volume before placing the object in the fluid, place the object in the fluid and record the volume after, subtract the initial from the total (liquid +object's displacement) and you will have the objects volume. However you must be aware that certain objects will float or at least have some amount of buoyancy making determining it's volume harder to ascertain (if at all possible) with this method.
You need more information. It all depends on the size of the cylinder
The buoyant force on an object is equal to the weight of the fluid displaced by the object. To calculate the buoyant force on the 446 gram cylinder, you need to know the density of the fluid it's submerged in and the volume of the cylinder. Using the formula Buoyant force = Density of fluid x Volume of object x gravitational acceleration, you can find the buoyant force acting on the cylinder.
To find displaced volume, you can immerse the object in a fluid and measure the volume of fluid displaced. The volume of fluid displaced is equal to the volume of the object. Alternatively, you can use geometric formulas or 3D modeling software to calculate the volume of the object directly.
certain fluid at 10 bar is contained in cylinder behind a piston ,the initial volume being 0.05 m3 calculate the work done by the fluid when it expands reversibly i) according to a law P=(A/ V2 ) -(B/ V) ,to a final volume of 0.1 m3 and a pressure of 1bar,where A and B are constants.Answer(19200 j)
To calculate the rise in the water level when a spherical ball is immersed in water in a vertical cylinder, you can use the Archimedes' principle, which states that the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The volume of water displaced by the ball is equal to the volume of the ball. Calculate the volume of the ball using the formula for the volume of a sphere, then use this volume to determine the rise in water level.
Level with the bottom of the fluid's meniscus
A graduated cylinder is simply a beaker with parallel sides and equally spaced volume markings along the side. As the sides are parallel the volume increases proportionately to the level of fluid in the beaker. Equally spaced markings ("graduations") are marked on the side of the cylinder to indicate the volume of fluid to that point.If you are using a graduated cylinder you will notice that the level of fluid (eg water) will seem to cling to the sides of the glass near the edge in a small radius due to the surface tension of the fluid. This radius is called the miniscus. Always read the volume of fluid from the marking at the bottom of the miniscus.
The volume of a cylindrical container is dependent on the container's dimensions. Here is the formula for Volume of a cylinder. Volume = π * R2 * H Where r Is the radius of the circular end of the container, and H is the height of the container.
Check out "horizontal cylindric segment" in Wolfram Alpha Online. That is the correct term for the solid you are looking for. Wolfram Alpha - "The solid cut from a horizontal cylinder of length L and radius R by a single plane oriented parallel to the cylinder's axis of symmetry (i.e., a portion of a horizontal cylindrical tank which is partially filled with fluid) is called a horizontal cylindrical segment."
A graduated cylinder is simply a beaker with parallel sides and equally spaced volume markings along the side. As the sides are parallel the volume increases proportionately to the level of fluid in the beaker. Equally spaced markings ("graduations") are marked on the side of the cylinder to indicate the volume of fluid to that point.If you are using a graduated cylinder you will notice that the level of fluid (eg water) will seem to cling to the sides of the glass near the edge in a small radius due to the surface tension of the fluid. This radius is called the miniscus. Always read the volume of fluid from the marking at the bottom of the miniscus.
Yes, energy as work can be transferred to an incompressible fluid in an insulated cylinder fitted with a frictionless piston. This is because the fluid is incompressible, so the volume does not change as the piston moves. It allows work to be transferred to the fluid without any change in pressure or volume.
Check out "horizontal cylindric segment" in Wolfram Alpha Online. That is the correct term for the solid you are looking for. Wolfram Alpha - "The solid cut from a horizontal cylinder of length L and radius R by a single plane oriented parallel to the cylinder's axis of symmetry (i.e., a portion of a horizontal cylindrical tank which is partially filled with fluid) is called a horizontal cylindrical segment."