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What is the final volume of a balloon that was initially 500.0 mL at 25C and was then heated to 50C?
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A balloon contains 5.5 L of air at 303 K and 101.3 kPa After an hour the air inside the balloon cools to 297 K What is the final volume of the air in the balloon?
Using the ideal gas law (PV = nRT), we can calculate the number of moles of air in the balloon at the initial conditions. Then, using the new temperature and the same number of moles, we can calculate the final volume of the air in the balloon. The final volume will be less than 5.5 L due to the decrease in temperature.
What will a balloon that has a volume of 6 cubic inches at 99 feet have when it is at 33 feet?
The volume of a balloon is proportional to the pressure it is under, so if the volume is 6 cubic inches at 99 feet, it would have a different volume at 33 feet. To find the new volume at 33 feet, you would need to use Boyle's Law, which states that the initial pressure times the initial volume equals the final pressure times the final volume. So, you would use the formula P1V1 = P2V2 to solve for the new volume at 33 feet.
When a balloon is heated its volume doubles What is happens to its density?
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
A balloon that contains 0.75 L of a gas at 25°C is cooled to –100°C. Calculate the new volume of the balloon.?
Using the ideal gas law, we can calculate the new volume of the balloon. Given that the initial volume is 0.75 L, the initial temperature is 25°C (298 K), and the final temperature is -100°C (173 K), we can use the equation (V1/T1) = (V2/T2) to find the new volume. Plugging in the values, we get V2 = (0.75 L * 173 K) / 298 K ≈ 0.44 L.
What happens to the volume of air when it is heated?
The volume of air increases proportionally as it is heated, according to the formula: PV/T = P'V'/T' Where P, V, and T are initial values for pressure, volume and temperature in absolute terms and P',V',and T' are the final values with a constant pressure the equation becomes: V/T = V'/T' to solve for final volume the equation is: VT'/T = V' if V=1cu. meter, T = 200K and T' = 300K then 1 cu.meter x 300K/200K = 1.5 cu.meter
A balloon contains 5.5 L of air at 303 K and 101.3 kPa After an hour the air inside the balloon cools to 297 K What is the final volume of the air in the balloon?
Using the ideal gas law (PV = nRT), we can calculate the number of moles of air in the balloon at the initial conditions. Then, using the new temperature and the same number of moles, we can calculate the final volume of the air in the balloon. The final volume will be less than 5.5 L due to the decrease in temperature.
What is the final volume of a balloon that was initially 500.0 mL at 25 degrees Celsius and was then heated to 50 degrees Celsius?
Change Celsius to Kelvin by adding 273.15. 25 C = 298.15 K 50 C = 323.15 K An equality. 500.0 ml/298.15 K = X ml/323.15 K 298.15X = 161575 X = 541.925 milliliters -------------------------------you do significant figures
If you have 45L of helium in a balloon at temperature of25c and increased the temperature of the balloon to 55c what will the new volume of the balloon be?
To find the new volume of the balloon, you can use the ideal gas law formula: V2 = V1 * (T2/T1), where V1 is the initial volume (45L), T1 is the initial temperature (25°C), and T2 is the final temperature (55°C). Plugging in the values, V2 = 45 * (55/25) = 99L. So, the new volume of the balloon would be approximately 99 liters.
How hot must the air in a balloon be heated if initially it has a volume of 750 L at 20 degrees celsius and the final volume must be 1000 L?
The way to keep this simple is to assume that the pressure in the balloon remains constant throughout the operation. The only trick to this whole thing is to understand that-- At constant pressure, volume is directly proportional to temperature.Volume2/Volume1 = Temperature2/Temperature1-- 'Temperature' means absolute temperature ... Kelvin, or (Celsius + 273).? The initial temperature of 20 C is absolute temp of 293 K.If the pressure remains constant, thenAbsolute-temp2 = Absolute-temp1 x (Volume2/Volume1) = 1,000 x 293/750 = 3902/3 K.°Celsius = Absolute - 273 = 117 2/3 ° C.
If initial volume is smaller than the final volume?
If the initial volume is smaller than the final volume, this suggests that there has been an increase in volume. This could be due to factors such as expansion of a substance when heated, addition of more material, or a phase change from a more condensed state to a less condensed state.
What will a balloon that has a volume of 6 cubic inches at 99 feet have when it is at 33 feet?
The volume of a balloon is proportional to the pressure it is under, so if the volume is 6 cubic inches at 99 feet, it would have a different volume at 33 feet. To find the new volume at 33 feet, you would need to use Boyle's Law, which states that the initial pressure times the initial volume equals the final pressure times the final volume. So, you would use the formula P1V1 = P2V2 to solve for the new volume at 33 feet.
When a balloon is heated its volume doubles What is happens to its density?
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
A balloon that contains 0.75 L of a gas at 25°C is cooled to –100°C. Calculate the new volume of the balloon.?
Using the ideal gas law, we can calculate the new volume of the balloon. Given that the initial volume is 0.75 L, the initial temperature is 25°C (298 K), and the final temperature is -100°C (173 K), we can use the equation (V1/T1) = (V2/T2) to find the new volume. Plugging in the values, we get V2 = (0.75 L * 173 K) / 298 K ≈ 0.44 L.
What happens to the volume of air when it is heated?
The volume of air increases proportionally as it is heated, according to the formula: PV/T = P'V'/T' Where P, V, and T are initial values for pressure, volume and temperature in absolute terms and P',V',and T' are the final values with a constant pressure the equation becomes: V/T = V'/T' to solve for final volume the equation is: VT'/T = V' if V=1cu. meter, T = 200K and T' = 300K then 1 cu.meter x 300K/200K = 1.5 cu.meter
When a solid is heated and then pressed to form a new shape Is its area remains constant or volume or both?
Assuming that none of the solid evaporated during the time that it was being heated, then the mass must be conserved. Then, assuming that after the object is in its' final shape the density of the material returns to its' original value the volume must be unchanged. This is because mass = volume * density. However, the surface area does not have to be the same.
A weather balloon full of helium with a volume of 47.1 L at 22oC is sitting inside an aircraft hangar The temperature of the hangar increases to 33oC Which equation would be easiest to use to find t?
(v1/t1) = (v2/t2)
What is the final concentration of a solution prepared by diluting of HCl to a final volume of?
To find the final concentration of a solution after dilution, you can use the formula: (C_1V_1 = C_2V_2), where (C_1) is the initial concentration, (V_1) is the initial volume, (C_2) is the final concentration, and (V_2) is the final volume. Plug in the values for the initial concentration, volume, and final volume to calculate the final concentration of HCl.
