0
s + 3 = 6s -s
-s
-------------
3 = 5s /5
/5
s=3/5 or s=.6
s3 - 3s2 + 9s - 27
= s2(s - 3) + 9(s - 3)
= (s - 3)(s2 + 9) or
= (s - 3)(s2 - (9i2)
= (s - 3)(s - 3i)(s + 3i) if you want to find for what values of s the expression equals to zero, then this happens when
s - 3 = 0 or s - 3i = 0 or s + 3i = 0
s = 3, ±3i
There are 3 1's in 3.
3's are counting by 3's you can count like this 3,6,9,12,15,18,21,24,27,30
If s-5=3 then the value of s is 8 !