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s + 3 = 6s -s

-s

-------------

3 = 5s /5

/5

s=3/5 or s=.6

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s + 3 = 6s -s

-s

-------------

3 = 5s /5

/5

s=3/5 or s=.6

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s3 - 3s2 + 9s - 27

= s2(s - 3) + 9(s - 3)

= (s - 3)(s2 + 9) or

= (s - 3)(s2 - (9i2)

= (s - 3)(s - 3i)(s + 3i) if you want to find for what values of s the expression equals to zero, then this happens when

s - 3 = 0 or s - 3i = 0 or s + 3i = 0

s = 3, ±3i

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There are 3 1's in 3.

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3's are counting by 3's you can count like this 3,6,9,12,15,18,21,24,27,30

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If s-5=3 then the value of s is 8 !

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