1000000 is Ten to the Power of Six
P=s r t , so, s= P/(st)
11 players in a soccer team
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s-t=2(iw)=p. There you go
h t t p s :/ / y a z i n g . c o m / d e a l s / b l u e h o s t / P a p i t o T 1 7 Remove spaces
h t t p s :/ / y a z i n g . c o m / d e a l s / b l u e h o s t / P a p i t o T 1 7 Remove spaces thanks you and good luck!!
From the left, it would be Child R, Child K, Child S, Child P, and Child T. So, K and P are on either side of S.
Suppose you have the fractions p/q and r/s. Let the LCM of q and s be t.Then t is a multiple of q as well as of s so let t= q*u and t = s*v Then p/q = (p*u)/(q*u) = (p*u)/t and r/s = (r*v)/(s*v) = (r*v)/t have the same denominators.
Prove: [ P -> Q AND R -> S AND (P OR R) ] -> (Q OR S) -> NOT, --- 1. P -> Q ___ hypothesis 2. R -> S ___ hypothesis 3. P OR R ___ hypothesis 4. ~P OR Q ___ implication from hyp 1. 5. ~R OR S ___ implication from hyp 2 6. ~P OR Q OR S ___ addition to 4. 7. ~R OR Q OR S ___ addition to 5. 8. Let T == (Q OR S) ___ substitution 9. (~P OR T) AND (~R OR T) ___ Conjunction 6,7 10. T OR (~P AND ~R) ___ Distribution from 9 11. T OR ~(P OR R) ___ De Morgan's theorem 12. Let M == (P OR R) ___ substitution 13. (T OR ~M) AND M ___ conjunction 11, hyp 3 From there, you can use distribution to get (T AND M) OR (~M AND M). The contradiction goes away leaving you with T AND M, which can simplify to T.
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