# How many feet per second will a car travel at 52 mph?

ANSWER: 52 miles per hour equals 274560 feet per hour, divided by 60: equals 4576 feet per minute, divided by 60: equals 76.266666 or 76.27 feet per second.

# How many feet does it take to stop a car traveling at 15 mph?

At 25 miles per hour, it takes you about 62 feet to stop a car, reaction time is added in. for a driver who is alert and well rested, in good health and not impaired by alcoho…l or medication. weight of car and load can very these figures.

# How many feet per second does a car travel when it is moving at 25 mph?

36.6 feet per second at 25 miles per hour.

# How many feet will a car travel at 50 mph?

50 miles per hour is 50 * 5280 (feet per mile) per hour = 264000 feet per hour and then, depending on how long a time period you're interested in...you could just divide the 2…64000 feet per hour by 60 to find the distance in feet per minute...then divide that again by 60 to find the distance in feet per second. A car will travel 264000 feet per hour at 50 mph. 264000 feet per hour / 60 minutes per hour = 4400 feet per minute 264000 feet per hour / 3600 seconds per hour = 73.33 feet per second

# How many feet per second does a car travel at 20 mph travel?

At 20 mph, a car is moving at about 29.3 feet per second.

# If a car is traveling 15 mph how many feet will it travel per second?

22 feet per second.

# How many feet will a car travel at 60 mph?

316, 800 ft/hr

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# How many feet does it take to stop car at 25 mph?

A vehicle travels approximately 1.5 ft per second for each mile per hour. 25 x 1.5 = 37.5. Add to that the average human response time to react to stimuli and apply the brake …(1.5 sec again) = 56.25 ft before the vehicle begins to stop. Braking on most decent surfaces with good tires slows you 15 feet per second, per second of braking. 37.5 fps to 0 fps = 2.5 sec to stop (37.5 fps/2) x 2.5 sec = 46.875 ft braking distance + 56.25 reaction distance = 103.125 ft between recognition of a danger and your vehicle stopping. Add to that the braking efficiency of the vehicle. You can also account for the drag coefficient of the pavement and grade (.7 to .8) but that is usually a negligible amount unless you are doing serious traffic crash reconstructions.

# At 25 mph how many feet per second does a car travel?

At 25 miles per hour, a car travels: 36.67 feet per second.

# At 50 mph how many feet per second does a car travel at 50 mph?

At 50 mph, a car travels 73.33 feet every second.

# How many feet per second does a car travel at 35 mph?

1 Mile per Hour = 1.46666666666667 Feet per Second 35x1.46666666666667= around 51 feet per second..

Answered

In Algebra

# How many feet will a car travel in 1 second at 53 mph?

77.73 feet every second.

Answered

In Science

# How many feet per second does a car travel at 50 mph?

50 mph = 73.3 feet per second.

Answered

# How many feet per second does a car travel going 45 mph?

45 mph (5280 feet/1 mile)(1 hour/3600 seconds) = 66 feet per second

Answered

In Science

# How many feet does a car travel at 50 mph?

That depends upon for how long it is moving: Every day it will travel 50 miles/hr x 5280 ft/mile x 24 hr/day = 6336000 ft/day Every hour it will travel 6336000 ft/day ÷ 2…4 hr/day = 264000 ft/hr Every minute it will travel 264000 ft/hr ÷ 60 min/hr = 4400 ft/min Every second it will travel 4400 ft/min ÷ 60 sec/min = 731/3 ft/sec ≈ 73.33 ft/sec * Added - The simple formula that should be used is converting MPH to feet per second (FPS). This is done by multiplying by 1.467, or for an easy rough estimate, 1.5. This result in 50mph = 73.35 fps. This is the method most often used by engineers and accident investigators. This can be used for determining braking distances for a car as well, once the deceleration rate is identified.

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In Science

# At 25 MPH it will take you about how many feet to stop a car?

The Uk Highway Code uses the formula: [Emergency] overall_distance = thinking_distance + stopping_distance with: thinking_distance = speed_in_mph ÷ 1 ft/mph stopping_…distance = speed_in_mph² ÷ 20 ft/mph² ie the thinking_distance is 1 ft per 1 mph, so at 25 mph, this would be 25 ft; and the stopping_distance in feet is given by speed_in_mph squared divided by 20; for 25 mph this would be 25² ÷ 20 = 31.25 ft So it takes about 31 ft (9.5 m) to stop a car from 25 mph. Overall in an emergency it would take approx 25 + 31 = 56 ft (about 17 m), but the thinking_distance is very dependent upon the alertness of the driver. Note: these formulae have not been updated for the improvements in car brakes, and the SAME distances are used when considering stopping a 23 tonne coach!