7.3x10^4 g
Boron is a metal element. Atomic mass of it is 11.
To calculate the density, you need two things. Mass and volume. Here you have a mass of 275 grams. 588 cm square is an area and not a volume. So you can not calculate the density here.
Grams can't be converted to milliliters. Grams measure mass, while milliliters measure volume.
The apple would most likely have a mass of 250 grams
Mass and volume. You divide the mass by the volume to get density with the corresponding units. Mass and volume. Density = mass/volume Often, mass is in grams and volumes in milliliters. Water has a density of 1g/ml. Air has a density of about 0.0013g/ml. Lead has a density of 11.34g/ml.
7.3x10^4 g
11
Boron has a density of 2.34 grams per cubic centimeter. A link is provided. It also has a mass of 10.811 grams.
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
The formula mass for boron nitrate is 197 grams per mole.
Grams are mass. There's no calculation involved.
This mass is 101,6505 g.The atomic masses of hydrogen and boron are 11 and 1 respectively. The relative molecular mass of the compound is 14. Therefore the mass of 7.35 moles is approximately 102.9 grams.
mass (g) = atomic wight / Avogadro's number Avo = 6.022x10^23
grams and to calculate use a pan balance
I would guess 250 grams.
you take the atomic mass of the atom (or molecule) and you have the mass in grams
For any element, subtract the atomic mass from the atomic number.