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How do you differentiate 2sinAcosA?

Updated: 4/28/2022
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12y ago

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First using the double angle formula;

2sinAcosA = sin(2A)

Therefore d/dA (sin2A) = cos(2A) * 2 = 2cos(2A)

We multiply by the two due to the chain rule, where we must multiply by the derivative of the angle.

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