How do you factor c square minus 5c plus 6?

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(c - 2)(c - 3)
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Factor 25a squared minus 20ab plus 4b squared?

This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number.. 25a(2) - 20ab + 4b(2). (2b-5a)(2b-5a). This is:. 2bx2b=4b(2). 2bx-5a=-10ab (twice). -5ax-5a=25a

How do you factor x squared plus x minus 1?

Normally when you factor a polynomial, it is to make a problem easier. This is a polynomial of the form ax 2 + bx - c, where a=b=c=1. Since a=1, to factor this polynomial nicely we would have to find two factors of c=1 that add up to b=1. Since the factors of 1 are -1 and 1, the possible numbers to (MORE)

Factor x squared plus x minus 10?

to factor this equation you need to use the quadratic formula: in this question a=1, b=1, c= -10 so after you plug in those number you answer would be: x= (-1+ or - the square root of -39) divided by 2

How do you factor 2x squared minus 13x plus 15?

This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 15, which is 30. Then you need to find the factors of thirty, i.e. 3 and 10, 15 and 2, 5 and 6. You need to find the pair of factors that add to make -13x, which woul (MORE)

How do you factor 2x cubed minus 5x squared plus 5x minus two?

2x 3 - 5x 2 + 5x - 2 = x(2x 2 -5x+3) + 2x - 2 = x(2x-3)(x-1) + 2(x-1) = (x-1)[x(2x-3)+2] = (x-1)(2x 2 -3x+2) I did it by trial and error, through experience -- no set procedure. (2x 2 -3x+2) cannot be factored, which is evidenced by calculating (b 2 -4ac), where a = 2; b=-3; and c=2 fro (MORE)

How do you factor 2x squared minus 5x plus 2?

Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).

How do you factor w squared minus 13w plus 48?

w 2 - 13w + 48 You want to write the equation in the form (w+a)(w+b). However, if this particular equation could be written in this form, there would be at least one value of x where y = 0. There are no such solutions for this equation, so it cannot be factored into this form. However, you can fa (MORE)

X squared plus 3x minus 6?

X 2 +3x-6=0 A=1 B=3 C=-6 D=B 2 -4AC=3 2 -4*1*-6=33 X1= (-B+√D)/(2A)=(-3+√33)/(2*6)=1,372281323 X2= (-B-√D)/(2A)=(-3-√33)/(2*6)=-4,372281323

How do you factor z squared plus 7z plus 6?

The procedure for factoring z 2 +7z+6 is as follows: First, we must look at the number in front of the first variable. In this case, it is a 1. Then we look at the last number in the expression, which is a 6 (the expression must be arranged in descending order by the exponents of the variab (MORE)

What are the factors of q cubed minus q squared plus 2q minus 2?

q 3 - q 2 + 2q - 2 = (q 2 + 2)(q - 1). * If you are prepared to enter the realm of complex numbers (where i = √(-1) ), then (i√2) 2 = 2(i 2 ) = -2, and q 2 + 2 = q 2 - (i√2) 2 = (q - i√2)(q + i√2); and, in this case, the complete factorizat (MORE)

Factor X squared plus 2x minus 8?

1) Find two numbers that multiply to -8 and add to 2. Factor of (-8) Sum of (2). This is 2 * (-4)= -8 and -2 + 4= 2. 2) Then put it in factor mode. (X-2)(X+4). Use distributive property. 3) After that, set it to 0. 0= X-2 Add (+) 2 to both sides. Cross out the negative and positive 2's. 0 + 2 is 2 (MORE)

What are the factors of 6x squared plus 7x minus 5?

We are looking for a factorization like 6x² + 7x - 5 = (_x + _)(_x - _) where we need to fill in the numbers in the blanks. Since the first and third blanks multiply to 6, they have to be 1 and 6 or 2 and 3. Similarly, the second and fourth blanks multiply to 5 so they must be 1 and 5. By t (MORE)

How do you factor 12t squared minus t plus 4?

That doesn't factor neatly. Applying the quadratic formula, we findtwo imaginary solutions: (1 plus or minus the square root of -191)divided by 24 t = 0.0416666 repeating + 0.5758447900452189 i t = 0.0416666 repeating - 0.5758447900452189 i where i is the square root of negative one.

How do you factor 3x squared minus 16x plus 5?

3x 2 - 16x + 5 = 3x 2 - x - 15x + 5 = x(3x - 1) - 5(3x -1) = (3x - 1)(x - 5) or I would use the quadratic equation. 3X^2 - 16X + 5 = 0 X = -b +/- sqrt(b^2-4ac)/2a a = 3 b = -16 c = 5 X = -(-16) +/- sqrt[(-16)^2 - 4(3)(5)]/2(3) X = 16 +/- sqrt(256 - 60)/6 X = 16 +/- (MORE)

How do you factor 2u squared plus 13u plus 6?

I don't factor these. I am lazy, so I use the quadratic formula. -b +/- sqrt(b^2-4ac)/2a a = 2 b = 13 c = 6 u = - 13 +/- sqrt[13^2 - 4(2)(6)]/2(2) u = - 13 +/- sqrt(121)/4 u = [- 13 +/- 11]/4 u = - 1/2 u = - 6 My TI-84 confirms this answer. You check in original equation. (MORE)

How do you factor c squared minus 7c plus 10?

To factor this equation... if you have learned before, find 2 numbers that add up to the middle value (-7) and multiply together to have a product of the last value (+10). You can use guess and check for this problem... but if you haven't already found it... the sum of -5 and -2 is -7... and the pr (MORE)

A minus b plus c whole square?

If you mean (a-b+c)^2, then... . a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 . = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.

How do you factor x squared minus 9x plus 16?

Since there is an x 2 , we can do this step first: (x )(x ) For this question, we need to use the quadratic formula: -b±√(b 2 -4ac) ----------------- 2a Let me explain some of the symbols and letters first. ±- is the plus or minus sign. You will perform both separately wh (MORE)

How do you factor 3x squared minus 15x plus 16?

You will find it too difficult to factor this expression. If you wish to solve for the roots of this quadratic you first need to know what the expression is equal to (so you can write it in the form of ax 2 + bx + c = 0) and then you should use the quadratic formula instead. x = (-b + or - (MORE)

How do you factor 2x squared minus 77x plus 119?

2x^2-77x+119 It is not factorable if you are looking for integral factors (whole numbers). You might be able to use the quadratic formula if you wish to solve for the zeros (x-intercepts) of it.

What are the factors of 3X squared minus 14X plus 8?

(x - 4)(3x - 2) 3X 2 - 14X + 8 = 0 X = - b (+/-) sqrt(b 2 - 4ac)/2a a = 3 b = - 14 c = 8 X = - (- 14) (+/-) sqrt[(- 14) 2 - 4(3)(8)]/2(3) X = 14 (+/-) sqrt(196 - 96)/6 X = 14 (+/-) sqrt(100)/6 X = [14 (+/-) 10]/6 X = 4 ---------- X = 2/3 -----------------check (MORE)

How do you factor 2x squared plus 3x equals 3x minus 1 squared minus x squared?

If you mean 2x 2 + 3x = (3x - 1) 2 - x 2 Then you can solve it this way: Expand: 2x 2 + 3x = 9x 2 - 6x + 1 - x 2 Group like terms: 2x 2 + 3x = 8x 2 - 6x + 1 6x 2 - 9x - 1 = 0 Complete the square: 6x 2 - 9x = 1 x 2 - 3x/2 = 1/6 x 2 - 3x/2 + 9/16 = 1/6 + 9/16 (x - 3/4) 2 = 8/48 + 27 (MORE)

How do you factor x squared minus x plus 2?

This equation (where the above expression equals 0) has imaginary roots and so will need to be solved using the quadratic formula and the use of the imaginary number i .

How do you factor 2y squared plus 9y minus 2?

2y 2 + 9y - 2 this will not factor using integers what is what most algebra teachers will tell you is 'prime' but ... make an equation ... 2y 2 + 9y - 2 = 0 use the quadratic formula to solve y = [-9 (+/-) sq rt (81 -4x2(-2))] / (2x2) y = [-9 (+/-) sq rt (97)] / (4) now separate these y = (MORE)

What are the factors of 3x squared minus x plus 4?

That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (1 plus or minus the square root of -47) divided by 6. x = 0.16666 + 1.142609100066840 i = 1 st root = r 1 x = 0.16666 - 1.142609100066840 i = 2 nd root = r 2 where i is the square root of neg (MORE)

What are the factors of 6x squared plus 7x plus 6?

That doesn't factor neatly. Applying the quadratic formula, we findtwo imaginary solutions: (-7 plus or minus the square root of -95)divided by 12. x = -0.583333 repeating + 0.8122328620674136 i x = -0.583333 repeating - 0.8122328620674136 i where i is the square root of negative one.