by connecting ampere meter in series with load.
The power used up by any electrical load is . . .(voltage across the load) x (current through the load) or (voltage across the load)2/(resistance of the load) or (current through the load)2 x (resistance of the load). These are all completely equivalent, and you have your choice of which oneto use, depending on which numbers you know or can measure.
The power used up by any electrical load is . . .(voltage across the load) x (current through the load) or (voltage across the load)2/(resistance of the load) or (current through the load)2 x (resistance of the load). These are all completely equivalent, and you have your choice of which oneto use, depending on which numbers you know or can measure.
The unit of measure for current load is amperage, or simply amps.
after incomer & before outgoing feeder, we connect ameter to measure amps.AnswerThe voltmeter is connected in parallel with the load and the ammeter is connected in series with the load, if you wish to measure the potential difference across, and the current through, that load.
Without load there is no current so it is impossible to measure it.
Reactive current through inductive load produces -- Magnetic field
As the no load current is the current due to core losses of the motor which is very small .in no load terminals are open circuited no current flows through it, a small current flows which is due to core
It measuring by pressing the red button
an off-load device a a switch where there is no current passing through it when its switched, a isolator is a off load device, a light switch is a on-load device because there is current passing through it when its switched.
Measure the current and voltage on the secondary side.
The current flowing through a transformer's secondary is the current drawn by the load, so it will be exactly the same as the current flowing through your induction motor -assuming that is the load. Don't really understand the point of your question!
As the circuit must be a closed loop, the current passes through both the source and load. If it was not a closed loop no current could flow anywhere.