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How do you solve similtaneously -5a plus b equals 2 and -a -5b equals 0?
Wiki User
∙ 14y ago
-5a + b = 2 AND -a - 5b = 0
-5a + b = 2
b = 2 + 5a
*using above
-a - 5b = 0
-a - 5(2 + 5a) = 0
-a - 10 - 25a = 0
-26a = 10
a = 10/-26
*using 'a' value
5a + b = 2
5(10/-26) + b = 2
-25/13 -2 = -b
b = 51/13
Therefore
a = 10/-26
b = 51/13
Wiki User
∙ 14y ago
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