How long does it take a 10 pound object to fall 30 feet?

Answer 1

Assuming on the Earth where g = 9.8 m/sec2 and we neglect air drag, and the object started at rest (zero initial velocity) then:

d = V0*t + (a*t2)/2; with d = distance, V0 = initial velocity, a = acceleration, and t = time.

If V0= 0 and a = 9.8 m/s2, then: 30 m = (4.9 m/s2)*t2

t2 = (30 m) / (4.9 m/s2) = 6.122449 s2 ; t = sqrt(6.122449 s2) = 2.4744 seconds

Answer 2

The formula is Time = Square root of(2 distance/9.82metre per second per second )

Time = square root (2 x 9.144 divided by 9.82 metres per second squared)

Time = square root of 18.28 divided by 96.43

Time = square root of 0.185

Time to fall = 0.43 seconds (ish)