I'm going to restate the question so you know for sure what question I'm answering, because I'm not positive I know what question you're trying to ask.
Given five distinct objects, how many ways is it possible to select three of them if order matters?
There are 5 choices for the first digit/object.
There are 4 choices for the second digit/object.
There are 3 choices for the third digit/object.
So there are 5x4x3 = 60 possible combinations.
It appears that only single digit numbers work (0 thru 9)
Different schemes have different id numbers of different lengths.
Write out the numbers 1 to 100. Count the number of times 1 appears.
If you use each number once, there are six combinations.
Digits is how many numbers you have in a number. If you have the number 4 it has one digit if you have the number 20 it has two digits and if you have the number 558 it has three digits. So basically in the number 1085 it has 4 digits because there is 4 numbers in it, the numbers are 1,0,8 and 5. Hoped you understand.
12689 14689 12489
36
Answer: I cannot answer this question. I do not know where the numbers start and end. Answer: Put negative numbers before positive numbers. For the positive numbers, the one with the least digits is smaller. For the same number of digits, compare each digit until you find a different number of digits. For the negative numbers, it is the opposite as for positive numbers.
Among whole numbers, 1,023,456 is.
The digit '6' appears most often (two times). The other digits only appear once.
Armstrong numbers are the sum of their own digits to the power of the number of digits.
roman numbers............