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The formula to calculate the heat energy to raise the temperature is

Q = m s (t2 - t1)

Here m- mass of the substance given as 1 kg.

s- specific heat capacity given as 900 J per kg per Celsius.

t1 initial temperature and t2 final temperature.

Plugging the values in the above expression we get,

Q = 1 x 900 x 80 = 72000 J or 72 kJ.

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Wiki User

14y ago
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14y ago

You've got this down to a simple case of multiplication already. How much energy is required? Why, 600 joules for each degree, per kilogram of granite. We only have one kilogram, so the only problem is the temperature rise.

The Temperature difference is (100-20) = 80 degrees celsius. 600 joules for each of the 80 degrees is a simple calculator problem, if you have one - 600*80.

If not, remember that you have, in effect, 6*10*10*8*10 which can be moved around to be 6*8*1000. Ignore the thousand, and do 6*8 - 48.

So we have 48*1000 joules. 1000 joules is one kilojoule, so that thousand we didnt use can just become a k -

We have 48kj of energy that need to be added.

Spelling this out so that you can use the same method in the future...

  • You can use the formula Q=cm(delta)T to solve such problems.
  • Q is the heat energy added, c is the specific heat, m is the mass and (delta)T is the change in temperature.
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Wiki User

14y ago

72,000,000 J or 72,000 kJ or 72 MJ (Mega Joules)

Specific heat is written as delta H * M * delta T (Change in heat * mass in grams * change in Temperature in Celsius or Kelvin)

So 900 J * 1000 g * 80 C = 72,000,000 J

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13y ago

10,400J

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April Powers

Lvl 4
4y ago

48,000 J

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Wiki User

15y ago

10,400 j

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Wiki User

13y ago

10,400 J

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Wiki User

12y ago

48,000 J

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Q: How much energy must be added to a 1-kg piece of gold with a specific heat of 130 J/(kg°C) to increase its temperature from 20° C to 100° C?
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