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What is the minimum energy required to lift an object weighting 200 newtons to a height of 20 meters?
Wiki User
∙ 11y ago
Increase in the object's potential energy = (force) x (distance) = (200) x (4) = 800 newton-meters = 800 joules
Power = (800 joules) / (4 seconds) = 200 joules per second = 200 watts
Wiki User
∙ 14y ago
Wiki User
∙ 12y agoTo lift an object that weighs 200N to a height of 4m requires 800 N-m = 800 joules of work (energy).
It makes no difference whether you do it in 4 seconds or 4 years. The change in the object's
potential energy is the same.
The rate at which you do that work is the power you use to do the operation.
-- If you do it in 4 seconds, it takes (800/4) = 200 watts of power.
-- If you do it in 0.4 seconds, it takes (800/0.4) = 2,000 watts. (2 kilowatts)
-- If you do it in 400 seconds (6 minutes 40 seconds), it only takes (800/400) = 2 watts.
Wiki User
∙ 14y agoForce to lift something = (mass) times (gravity)
Work (energy) = (force) times (distance) = (mass) x (gravity) x (distance)
Power = (work/energy done) divided by (time to do it)
= (mass) x (gravity) x (distance) / (time)
= (100) x (9.8) x (2) / (4) = 1960/4 = 490 joule/sec = 490 watts .
Wiki User
∙ 14y agoWork = (force) times (distance) = 500 x 4 = 2,000 newton-meters = 2,000 joules
Wiki User
∙ 14y agoE = mgh = Fh = 200*4 = 800 J
Wiki User
∙ 11y agoE=mgh=fh=200*20=4000
Anonymous
800N
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