x +y = 64
x divided by Y = 7 So what times seven equals a number close to 64
7x2 = 14
7x3 = 21
7x4 = 28
7 x5 = 35
7x6 = 42
7x7= 49
7x8 = 56 64 - 56 = 8
therefore x = 56 and y = 8 and to prove correct
56 + 8 = 64
56 divided by 8 = 7
64 & 8
The sum of the prime numbers 11 and 53 equals 64.
The numbers are 32.5 and 31.5
61 and 3
64
64 & 8
The two numbers are 64 and 8.64/8 = 864 + 8 = 72
The numbers are 98 and 64
The sum of the prime numbers 11 and 53 equals 64.
29 & 35
Find two numbers if their sum is 64 and their difference is 12. The two numbers are
The numbers are 32.5 and 31.5
There are two consecutive even numbers. The numbers are 62 and 64.
2 and 8
They are 36 and 64
They are 36 and 64
64