All we can deduce from that information is that k is a positive perfect square. Is that really the whole question?
What?
The value of k is 0
K= 18.666666
K+1 is as simplified as it gets. Unless you find the value of K. You can't add a variable and number.
k = 10 3k = 30 When a number appears next to a variable (like "k") it usually means multiply the number times the variable.
The equation for a circle of radius r and centre (h, k) is: (x - h)² + (y - k)² = r² If the centre is the origin, the centre point is (0, 0), thus h = k = 0, and this becomes: x² + y² = r²
k = 0.1
They are +/- 5*sqrt(2)
2
It is (-0.3, 0.1)
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2
Using the discriminant for a quadratic equation the value of k works out as plus or minus 12.
k = sqrt(160) = 12.6
If 'r' and 's' can be the same integer, then (1)3 = (1)2 , and k = 1 .If 'r' and 's' must be different integers, then (4)3 = (8)2 , and k = 64 .
The value of k is 0
0
If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6
0