Is spacetime absolute

Answer 1

Yes, "Spacetime is absolute". The idea of "spacetime " should be replaced with 4-space. Space is homogeneous. There is no time dimension. A point in space is p= r +ix +jy +kz= r + d where r is the real dimension of space and d is the three vector dimensions of space. Space is a quaternion space where i^2=j^2=k^2=ijk=-1.

There is no time intrinsically in space. Time can be introduced by recognizing that the real dimension r=ct where c is the speed of light. This would give p=ct + d and

p^2= (r^2- d^2) + 2rd= ( (ct)^2 - (x^2 + y^2 + z^2)) + ct(ix + jy + kz)

p^2= (ct)^2( 1 -(x^2 + y^2 + z^2)/(ct)^2 + (ix + jy + kz)/ct)

p^2= (ct)^2 (( 1- (v/c)^2) + 2v/c , where v=d/t.

Light is a scalar and c is a speed not a vector. Time is a scalar also not a vector, r, c and t are all real numbers or scalars, not vectors. Vectors are designated by i, j and k, unit vectors. The product of a vector and a real number is a vector. The product of a unit vector and a real is a vector.

Lorentz Contractions and Einstein's Relativistic mass are the result of treating light as a vector.

Relativity's Beta=v/c=cos(vr) is the redshift zand

Gamma = 1/sqrt(1 -(v/c)^2)= 1/sin(vr), where the angle vr is the angle between the radial center and the velocity vector v.

When v=c the angle is zero. As you can see gamma blows up at thiis condition. Relativity Theory also blows up on its " relativity spacetime ".

Einstein's Curvature of spacetime is another misconception of space . The deflection tangent is tan x= y/Rs where y is the deflection to earth over the distance to the sun. Tan x =1/2g(R/c)^2/R=1/2gR/c^2 where g is the gravitational constant on earth g=9.9. This gives tan x=8.25E-6 for angle 1.7'. Einstein's formula is whack and has nothing to do with the distance from the earth and the deflection to the earth.

There needs to be a major return to Absolute Space, quaternion Space.