Resistance is probably the missing word. I = e/R. If R is greater, I is less.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
increasing the voltage increases the current. this is because when you increase the voltage you make the pressure that is pushing on the current (which is making it move) greater, therefore increasing it. <<>> Ohms law states that, the current is directly proportional to the applied (EMF) voltage and inversely proportional to the resistance in a circuit. The formula you are looking for is I = E/R. You supply some figures for Voltage (E) and Resistance (R).
To reduce the losses, like I2r in the conductor and as per transformer principle when voltage is high , current is less. this means less equipment ratings, cost reduction, less line drop, more efficiency, less conductor size
An ideal voltage source has zero internal resistance so that the voltage stays constant with any load current. A practical voltage source should have less than 5% voltage drop at the rated load current.
The current through the circuit is directly proportional to the voltage across the circuit. The proportionality constant is 1/R, where 'R' is the total effective resistance of the circuit. C = V / R V = C R R = V / C
Less current, greater efficiency, reduced volt drop
Less current, greater efficiency, reduced volt drop
Less
A reverse current relay prevents a generator from discharging the battery when generator output is less than battery voltage. When generator output is greater than battery voltage, the reverse current relay closes and connects generator to electrical bus.
In the case of DC, and in AC when current and voltage are in phase, a volt-ampere is the same as a watt (and therefore, a kilo-volt-ampere is the same as a kW). In the case of AC, when current and voltage are NOT in phase, power = voltage x current x power factor; the power factor is the cosine of the angle between current and voltage, and it is always less than or equal to one. In such a case, a kVA would be less than a kW.
It will be greater:current = voltage / resistanceSince the bulb's resistance doesn't change, then current is a direct function of voltage.
Less current.
A reverse current relay prevents a generator from discharging the battery when generator output is less than battery voltage. When generator output is greater than battery voltage, the reverse current relay closes and connects generator to electrical bus.
Yes.
No. Power stays the same. Power is voltage times current. So, if voltage is doubles, current has be halved, less efficiency losses.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
increasing the voltage increases the current. this is because when you increase the voltage you make the pressure that is pushing on the current (which is making it move) greater, therefore increasing it. <<>> Ohms law states that, the current is directly proportional to the applied (EMF) voltage and inversely proportional to the resistance in a circuit. The formula you are looking for is I = E/R. You supply some figures for Voltage (E) and Resistance (R).