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The sum of three consecutive odd numbers is 41 more than twice the smallest number Find the largest of these three numbers?
Wiki User
∙ 8y ago
1. First: you must consider that the numbers that you are using are odd. (1,3,5...)
2. Use x as the variable for the numbers that you don't know.
so: x + (x + 2) + (x + 4) = 2(x) + 41
(2x is used b/c you are looking for the # that is 41 times more than twice (2) the smallest number (x). )
3. Simplify by bringing together like terms:
3x + 6 = 2x + 41
1x + 6 = 41
x = 35 (Your smallest number!)
Plug this into the other x variables & you get:
35 + 2 = 37
&
35 + 4 = 39
Those are your answers! (35, 37, 39)
But, I guess since it's just asking for the greatest of those, you'd just use 39.
Good luck!
Wiki User
∙ 8y ago
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