A #8 copper conductor with a 90 degree C insulation factor is rated at 40 amps.
Need to know what the wattage or the amperage is of the appliance. The load amperage is what governs the wire size and the breaker to protect the circuit.
The sizing of the circuit breaker and hence the wire size to feed the pump are all dependant upon the amperage of the pump. This question can not be answered without that information.
Wire and breakers are sized depending on the current that is to be applied to the circuit. To answer this question a voltage is needed to divide into the kilowatts to obtain this amperage. I = W/E. Once the amperage is obtained a table in the electrical code book is used to establish what the breaker size and wire size should be for that particular amperage.
The 225 amps is the secondary output amperage. Look on the machines nameplate to find the input amperage. It is that amperage that is needed to size the feed wire and there the breaker size. When you find that amperage you may want to re question the breaker size.
The use of a breaker in a circuit is to protect the wire size used in the circuit from becoming overloaded. Using the wattage of the load does not help for breaker sizing because the breaker operates on amperage. Amperage can be found from wattage by using the following equation. I = W /E. Amps = Watts / Volts. As you can see the amperage can not be calculated because there is no voltage stated.
Typically yes because that is what makes sense. However, the subpanel could have the same size breaker as long as the panel were rated for that amperage and the wire sizes were appropriate.
If you are talking about a breaker in a house panel then a 15 amp breaker would be used. It is the smallest amperage breaker that you will find in a house panel.
If the question means "two loads in one circuit" then the load currents have to be added together. The breaker that protects the circuit is sized for the total loading of the circuit. These two loads of course will be in parallel with each other. Find the wattage of the two loads if the amperage is not available. The equation is W = A x V. Watts = Amps x Volts. Once the total amperage of the circuit is found select the correct wire size for that amperage. The breaker protects the wire size so then select the proper breaker for that wire size.
It depends on what the amperage of the motor is. The motors amperage depends on the voltage of the motor. The higher the voltage the motor operates on the lower the amperage. So unless the amperage from the motor's nameplate is stated an answer can not be given.Just remember that the feeder capacity to the motor has to be 125% of the motors full load amperage and the breaker protecting the conductors to the motor has to be rated at 250% of the motors FLA. This higher breaker size allows the motor to start without tripping a normal size breaker that is rated for the lower conductor size.
A 15 amp circuit breaker will handle this situation very well. The smallest home breaker is rated at 15 amp.
The size of wire and breaker sizing are based on the current of the circuit. To answer this question a voltage must be stated or look on the ballast for the amperage and add that to the question.
The circuit breaker is used to protect the conductor that is connected to it from an overload condition. On a motor load the breaker has to be sized 250% of the motors full load amperage. Some circuits can be only loaded to 80% capacity and this is governed by the sizing of the breaker. Without knowing what the load amperage is, this question can not be answered.