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I image you are talking about a charge sensible force acting on a charged particle.

Let us image that a charged particle like an electron travels through an electromagnetic field sufficiently strong to remain almost unchanged by the presence of the charge itself.

The electromagnetic field is characterized by two vectors: the electrical field E and the magnetic induction field B. If the charge of our particle is q and its speed is v, the force F acting on the particle is

F = q E + q v X B

where X represent vector product. The first addendum is called electrical force, the second magnetic o Lorentz force (from the name of the scientist that discovered it).

The electrical force is associated to a change of the energy of the particle due to the electromagnetic field, if the charge is doubled the electrical force is also doubled, but it does not change its direction: the charged particle is still pushed in the direction of the electrical field.

The Lorentz force also double its intensity doubling the charge. Since the Lorentz force is always perpendicular to the velocity (due to the properties of the vector product) it does not change the particle energy (since the velocity intensity does not change), but induces a curvature in the particle trajectory. This curvature is greater and greater (the curvature radius gets smaller and smaller) while the charge increases.

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11y ago
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9y ago

The force of gravity between two masses is F= G m1 m2 / r2

So if the distance r is doubled we get (2r)^2 = 4 r^2

on the bottom, and on top we double the masses

2m1 x 2m2 = 4 m1 m2

then substituting in to the equation we see that the 4's cancel out on top and bottom so

F stays the same

Force does not change at all.

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15y ago

Force equals mass times acceleration, or F=MA. Do the math and the force is doubled.

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12y ago

it depends f=m*acceleration so there isn't a definite answer

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Q: How much does the force increase if each mass is doubled?
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