Mn2O7+Al=
mg07 *********************2nd Opinion**************** Nope, it is Mn2O7
MN m and 5 are the terms. 5 is the costant
In this case the roman numerals indicate the oxidation state of the cation portion of the polyatomic ion: [Fe(II)O2]2- as opposed to [Fe(III)O2]1- Mn(II)=Mn2+ Mn(VII)=Mn7+
4
m(n + 1)
Manganese (Mn)
Mn (maganese)
If the charge is positive number of electron will be 40, if the charge is negative it will be 44.As molybdenum has atomic number 42.
5mn + 6n - 14
Mn: 1s22s22p63s23p63d54s2 Mn2+: 1s22s22p63s23p63d5
Mn has 25 protons.
(m - 5)(n - 4)