Little "a".
that's all I figured out.
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
A byte
Looks like Binary, which is basically your computer using 1's and 0's to represent letters and numbers. The first string you have there 1011010 is the binary representation for the letter Z... the second one, looks like it has an extra character in there so it could be any number of letters.
The first step is to use a function to convert the number (integer, floating point or otherwise) into a string. The next step is to convert each character within that string to its binary equivalent. Converting an unsigned char to binary will require the use of bitwise operators, specifically &, << and >>. There are plenty of code snippets on the Web that show you how to accomplish this task, however it might be worth your while to work it out on paper first and then write the code. The best recommendation at this point is to explore bitwise operators in C and understand how binary math works. You'll likely find many uses for this knowledge in the future.
Number, string, binary string.
Not quite sure what you mean by "holes"; "binary data" consists of a string of ones and zeros.
Each 4-digit string of binary digits is equivalent to 1 single hexadecimal digit.
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
Computers only understand numbers (1 and 0) so for instance: the hex value for A = 60 - this is converted to a binary digit consisting of 1's and 0's which the computer understands, the binary representation of A = 1000001. Programs return or send hex strings for processing as a representation of the action being performed or a word and so on rather than returning several 0's and 1's. The ascii tables give a representaion of the keyboard imput and the coresponding hex values, there is a link below of one. When a user enters input the program receives this imput and sends to the computer processor, the computer converts to machine code or binary and the correct action is returned. Each character or action in machine language has a hex string representation, hex means the character is a base of 16. Html a = a Dec a = 97 Oct a = 141
sOutput has the value "12.3" (the string representation of 12.3f).
Eight binary digits are called a byte.Four binary digits are a nibble.
That depends on your string encoding. In ascii, for example: H = 72 = 1001000 i = 105 = 1101001