# What Is The difference between 5C and 18C?

13C or -13C depending on the order of subtraction

# Square coin from Neatherland has flowers on 1 side and a 5c and no date.is it a coin or metal?

I have one as well....all I can tell you is that there is a date on the saide of the coin that is 5c it is in the corner of the flowers and the coin I have 1923 tests to be si…lver

# What is the distance between points 1 -1 and -3 5?

distance = sqrt( (xf-xi)2 + (yf-yi)2 ) = sqrt( ((-3) - (1))2 + ((5) - (-1))2 ) = sqrt(52)

# What is the distance between points 2 4 and -1 -3?

Let us name the coordinates, to be easy to work and follow the answer:Point 1: x1=2 y1=4Point 2: x2=-1 y2=-3 In general, you can always place two different points (th…at are not at the same vertical or horizontal) on the Cartesian coordinate system, placed at the 2 non-rectangular corners of a rectangular triangle, see the "drawing" below: 1|\\| \\| \\+---2 The distance between two points is (using the Pitagoras theorem): distance2 = (x1-x2)2 + (y1-y2)2 In your case, distance2 = (2-(-1))2 + ((-1)-(-3))2therefore, distance2 = (2+1)2 + (-1+3)2distance2 = 32 + (-2)2distance2 = 9 + 4distance2 = 13Finally, the distance is the square root of 13 = 3.6 (approximately).

# What is the distance between point 4 5 and point 1 1?

The distance is 5. The x distance is 3, the y distance is 4, and the diagonal is sqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5

# What is the distance between the points 4 and 1 and -3 and 6?

The distance between these two points is 8.6. I found this by finding the difference between the two x values and the difference of the two y values. The difference between t…he x value was found like this: 4- (-3)= 7 and the difference between the y values was found the same way: 1-6=-5. Now to find the length between the two points, you need to use Pythagorean theorem because a right angle triangle is created with the difference between the two x values and the difference between the two y values. Lets call the length between these two points r. The formula to find r would be r^2= x^2 + y^2. r^2= (7)^2 + (-5)^2 r^2= 49 + 25 r^2= 74 r= square root of 74 r=8.6 You square root 74 because to get r by itself you have to square root r to get rid of the exponent.

# What is the distance between the points -3 3 and 1 -3?

7.2111 (rounded)

# What is the solution to this equation -5c plus 31 equals 1?

The value of c is 6

# What is the distance between the points -2 1 and 3 7?

58 * * * * * No. Distance squared = (-2 - 3)2 + (1 - 7)2 = 52 + 62 = 25 + 36 = 61 So distance = sqrt(61) = 7.8 approx.

# What is the distance between the points 3 and 7 and -3 and -1?

The distance between (3, 7) and (-3, -1) is sqrt{[(3 - (-3)] 2 + [7 - (-1)] 2 } = sqrt{[3 + 3] 2 + [7 + 1] 2 } =sqrt{[6] 2 + [8] 2 } = sqrt{36 + 64} = sqrt{100} = 10 uni…ts.

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In Geometry

# What is the distance between the points -4 3 and 3 -1?

Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8

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# What is the distance between the points -1 -5 and 5 3?

It is: (-1-5)2+(-5-3)2 = 100 and the sq rt = 10 which is the distance

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# What is the distance between points 2 2 and 1 1?

11 points

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In Algebra

# What is the distance between points (-6 1) and (-2 -2)?

Points: (-6, 1) and (-2, -2) Distance: 5 units

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In Science

# What is the distance between points 1 2 and 4 -1?

Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + …(y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2