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What is the energy of a 15 pounds 2x4 traveling at 100 mph and how does it compare to a high power rifle bullet with an energy of 2339 ft-lbf?
The formula for kinetic energy is KE=1/2(mass)(velocity)^2, therefore 15 lbs travelling at 100 MPH has a kinetic energy of 5,012 ft lbs or more than twice that of the bullet! To get the answer you have to convert 15 lbs to mass by dividing by the gravitational constant (32.2 Ft/sec^2) and converting 100MPH to ft/sec. 15x(100x1.467)^2/(2x32.2)=5,012
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A baseball weighs 145 grams 90 mph = 40.23 meters/sec KE = 1/2 mass x v2 = .5 x 145g x (40.23m/s)2 = 72.5g x 1618.45 m2/s2 = 117337.84 g m2/s2 = 117.34 kg m2/s2 = 117.34 J…oules
3000lbs = 1361 kg 60 mph = 26.8 meters/s kinetic energy = 1/2m*v^2 680.5 * 26.8^2 680.5* 718.2 = 488,735.1 joules ==== Alternative …presentation: KE = 1/2 (M) (V)2 = 0.5 x (3,000 lbs x kg/2.20462 lbs) x (60 mi/hr x 1,609.344 m/mi x hr/3,600 sec)2 = 489,500.1 joules (rounded)
I'm assuming you're talking about the .303 Savage (there's also a .303 British). It varies by a number of factors, with one of the foremost being barrel length. Generally spea…king, you can expect a velocity of around 2,090 ft/s (bullet velocities are usually expressed in ft/s rather than mph), but the actual results could vary greatly, again dependent on a number of factors.
761 mph (miles per hour) (The muzzle velocity of a bullet varies widely depending on the caliber, type of bullet, type of cartridge, the powder charge, and the gun barrel. Muz…zle velocities range from large caliber pistols as slow as 245 m/s, to high-powered rifles as fast as 1200 m/s, to tank rounds as fast as 1800 m/s. More .22 Long Rifle rounds have been produced than any other round.) Small short barreled pistols have low velocities around 340 mph. Long barreled rifles have velocities of 3,400 MPH Experimental rail guns have shot bullets at 7,602 MPH
Power is energy per unit time, or the rate at which electric energy is transformed. The amount of energy transformed is therefore power multiplied by time. (The above assumes …that power remains constant over the time considered. If not, advanced math - derivatives and integrals - must be used instead.)
How does kinetic energy affect the stopping distance of a vehicle travelling at 30 mph compare to the same vehicle travelling at 60 mph?
Kinetic energy equals one half times mass times velocity squared. If the velocity is doubled, from 30MPH to 60 MPH, the kinetic energy for the same mass would be four times gr…eater.
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m i…s the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force …(F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
Can't be answered without knowing the caliber, bullet weight and if it is fresh or salt water.
Temperature to an object with a lower temperature
It depends on several factors. Bullet can travel as slow as a few hundred feet per second up to several thousand feet per second. 1000 feet per second is about 682 MPH.
Kinetic energy of moving water You must first determine the mass of the water, and you must also do some unit conversion. Since you know the volume of water, you m…ust first determine its mass. One cubic foot of water weighs about 62.4 pounds (pound-force, lbf). But that's weight, not mass. What is the mass of 62.4 lbf of water? Since m = W/g, we get 62.3/32.2 = 1.93 slugs. (Note that the density of water varies with temperature, so the weight of a cubic foot of water will vary somewhat with temperature. It is densest at four degrees Celsius, but I chose to use the density of water at room temperature -- about 20 degrees C.) Miles per hour (mi/hr) is not a convenient unit, so convert to feet per second. One mi/hr = 1.47 ft/s, so 5 mi/hr = 7.33 ft/s. Kinetic Energy, Ek, is proportional to mass and the square of the velocity. It is given by the formula Ek = (1/2)mv2. Ek = (1/2)(1.93)(7.33)2 = 51.85 ft-lb (foot-pounds) = 70.3 joules.
An AR -15 will push a 5.56 2800 feet per second!
The kinetic energy of a 22500 lb truck traveling 55 mph is 1/2mv2 is 3084.808kJ.