1 day
Mathematically, The half life T 1/2 = (30 x 0.693)/ ln e (40/5) days = 30 x 0.693/ (3 x 0.693)
T1/2 = 10 days
Knowing that the half life is defined as the time for the activity (and correspondingly the material amount) by half.
Since the material is reduced from 40 to 5, it means it was reduced by three halfs (20, 10, 5). Accordingly 30 days = 3 T 1/2 or T 1/2 = 10 days
The half-life is 2 days.
1
1 day
10 minutes. APEX ^-^
Find the number of days (I refuse to futz around with a calendar for you). Divide it by the half-life, in this case 45 days. Raise 0.5 to that power (that's what the xy key on calculators is for). Multiply the resulting number by the original mass (here, 350 g) and there's your answer.
5.0 mg is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days.
After 48,2 days the amount of Th-234 will be 25 g.
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
18 days
1
It is 252 days.
1 day
0.013
0.00161
0.00425
3-5 days, 18-50 hour halflife
The halflife is 2.1 days. Multiply that by about 5 to get the time to decay to near zero.10.5 days or so.
0.013
10 minutes. APEX ^-^
It is 100 years.