In order to calculate that, it seems to me that you'd have to know how many numbers
exist all together, and how many pairs of numbers there are that sum to 10.
Since both of these are infinite, I'll say that the calculation is not possible.
Prob(Sum = 5) = 1/9
1/9
It's1/12
1/2
It is not possible to answer the question without knowing anything about the set of numbers that they are pulled from.
21/36 or 7/12 or 58.33...%
For 6 sided dice, there is only 1 way to get a 2: (1,1). There are 36 outcomes rolling 2 dice; so the probability of rolling two numbers whose sum is 2 is 1/36.
3
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
The probability of not rolling a sum of six with two fair dice is 1 minus the probability of rolling a sum of six. There are 36 permutations of rolling two dice. Of these, five sum to six, 1+5, 2+4, 3+3, 4+2, and 5+1. The probability, then of rolling a sum of six is 5 in 36. The probability, then of not rolling a sum of six is 31 in 36, or about 0.8611.
The probability that the sum of two dice is 7 is 6 in 36, or 1 in 6.Of all the combinations, this is the one with the highest probability.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36