If we plot these two points on a graph, we see that it is a straight horizontal line. Slope is found by taking rise/run. Now because the rise is 0, the slope of this line is 0.
Just divide the difference in y-coordinates (y2 - y1) by the difference in the x-coordinates (x2 - x1).
Points: (-1, -1) and (-3, 2) Slope: -3/2
2
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
|32 - 132| = |-100| = 100 |32 - 132| = |-100| = 100
y + 2x = 3xy + 2 - 2 = 3x - 2y = 3x - 2 this is the slope-intercept form of the equation of the line, y = mx + b, where slope m is 3, and the y-intercept b is -2.To find the x-intercept substitute 0 for y into the equation.y + 2 = 3x0 + 2 = 3x2/3 = 3x/32/3 = xThus the x-intercept is 2/3.
It has no slope.
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (-1, -1) and (-3, 2) Slope: -3/2
If you mean points: (-3, -5) and (3, 2) then the slope works out as 7/6
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
32
2
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
30
If you mean points of: (-1, -4) and (3, 2) Slope: 3/2 Equation works out as: 2y = 3x-5
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
Let : A ≡ ( x1, y1 ) ≡ ( 4, - 4), B ≡ ( x2, y2 ) ≡ ( 9, -1 ).Then, slope of line AB ism = ( y₂ - y₁ ) / ( x₂ - x₁ ) = (-1 + 4 ) / ( 9 - 4 ) = 3/5Hence, equation of line AB in Point-Slope Form isy - y₁ = m ( x - x₁ )y + 4 = (3/5) ( x - 4 ) .................... (1)5y + 20 = 3x - 125y = 3x - 32y = (3/5)x + (-32/5) ....................... (2)This is the Slope-Intercept Formy = mx + b.The form which is easier to get isSlope-Point Form. But this is one'spersonal choice.