Since the normal distribution is symmetric, the area between -z and 0 must be the same as the area between 0 and z. Using this fact, you can simplify this problem to finding a z such that the area between 0 and z is .754/2=.377. If you look this value up in a z-table or use the invNorm on a calculator, you will find that the required value of z will be 1.16. Therefore, the area between -1.16 and 1.16 must be approximately .754.
The Z value is 0.
z = ±0.44
In a standard normal distribution curve, one half of the area is .5 (or 50%). 0 is the middle value of the z-score. So, for an area of .7704, z must be negative. Also, the area from 0 to z (which is negative) must be equal to .2704. From the normal probability table, this value is -0.74 Therefore, the z-score for the area equals 0.7704 is -0.74
Approx 78.88 % Normal distribution tables give the area under the normal curve between the mean where z = 0 and the given number of standard deviations (z value) to its right; negative z values are to the left of the mean. Looking up z = 1.25 gives 0.3944 (using 4 figure tables). → area between -1.25 and 1.25 is 0.3944 + 0.3944 = 0.7888 → the proportion of the normal distribution between z = -1.25 and z = 1.25 is (approx) 78.88 %
See the attached link. The area that is read from the table is 1 - .9066 or .0934. Go to the body of the table for the value .0934 and the answer is -1.32. Therefore Z = -1.32.
The question does not specify what z is but this answer will assume that it is the value of a random variable with a Standard Normal distribution. That being the case, the area under the curve between those values is 0.4875.
The area is 0.9270, approx.
There cannot be such a value since the total area, being a probability, is 1.
Charts typically show and list the area to the left of the Z-Score value. To find the area to the right, just subtract the Z-Score value from 1; e.g. if the Z-Score value is .75 then take 1-.75 = .25.
2.224
0.97
The Z value is 0.
It is 1.17
What is the area under the normal curve between z equals 0.0 and z equals 2.0?
They refer to the same thing as do z-transformations.
z = ±0.44
In a standard normal distribution curve, one half of the area is .5 (or 50%). 0 is the middle value of the z-score. So, for an area of .7704, z must be negative. Also, the area from 0 to z (which is negative) must be equal to .2704. From the normal probability table, this value is -0.74 Therefore, the z-score for the area equals 0.7704 is -0.74