not enough information use a voltage drop calculator >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Use these two calculaters....... http://www.csgnetwork.com/voltagedropcalc.html or http://www.elec-toolbox.com/calculators/voltdrop.htm Good luck. Brian...
A: ANY CABLE will have a definite impedance and if current flow there is going to be a definite voltage drop because of it
It is mandatory to use a larger wire size to overcome voltage drop at the load.
For appliances that need a lot of power, the advantage of a higher voltage is that less current is needed, because power = voltage x current. That means that the cable doesn't need to be so thick. It also means that for a given percentage of voltage drop in the cable, the allowable volt-drop in the cable is higher when the supply voltage is higher. This also allows the use of a thinner cable especially when the cable is 100 ft long or more.
just apply the formula :-p=v*i*cos(angle);now you have the power rating,load so in turn power factor so you can easily calculate the value of current.with the help of current you can chose the cable available in the market either the aluminum or copper wiresatendra.svnit@gmail.com
Need to know the wire size of the core conductors.
31.5
It will decrease the voltage drop.
If the voltage is supplying any current through the cable, i.e. if there is any 'load' at the end, then the voltage will drop through the cable.
The voltage drop in a wire has nothing to do with the insulation. Voltage drop has to do with the cross sectional area of the wire.
cross sectional area of cable * voltage drop
A: ANY CABLE will have a definite impedance and if current flow there is going to be a definite voltage drop because of it
The voltage drop depends on the current through the cable.For DC current in cable of 16 mm diameter, at 68° F, the voltage drop is(0.00857) x (current, Amperes) volts.
It is mandatory to use a larger wire size to overcome voltage drop at the load.
Actual voltage would be 240V. 4 AWG copper is capable of carrying 50A. At 200 ft, with a 50A load, voltage drop would be about 6V, which is within the acceptable 3% voltage drop for a branch circuit.
to calculate the cable size of a run of 30 meters long you first will have to know the current of the appliance use the voltage drop formula V d = (mVxIxL)/1000 once the voltage drop is less than 2.5% of the nominal voltage, the cable should be upsize.
You shouldn't really have much voltage "drop". If you do, it usually means that there is a poor connection somewhere along your service line or inside wiring. Any significant amount of voltage drop can mean that you are at risk of a fire. On the other hand, line voltage into a house may not actually be 240 VAC. Measure the ACTUAL voltage with everything turned off, then see where it goes when you start turning things back on. The difference between the supplied voltage and the load voltage is the voltage "drop".
The formula for a simple DC voltage drop across a cable is:VDrop = Vmeasured at the input of cable - Vmeasured at the output of cableThis formula may seem simplistic however keep in mind that the sensitivity, accuracy and resolution of measuring instrument instrument is what is really important.If you know the DC current flowing through the cable and the impedance of the cable then you can use Ohm's law. Vdrop = I R where Vdrop is the voltage drop across the cable in volts I is the current flowing through the cable in amperes R is the resistance of the cable in ohms.ADDITIONALCalculation of the voltage drop is given by the formula belowVoltage Drop (Volt) = [(mV/Am)/1000] * I * lWhere mV/Am = millivolt drop per meter per ampere of the cable(this information is given in the table based on IEE Wiring Regulation)I = Current in the cable (in Ampere)l = Distance of cable (in Metre)See related links below