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The relationship between those four can be found from using the original centripetal force equation, Fc = (mv2)/r.

Since we know v=d/t, we can sub that into the equation to get Fc=(md2)/(rT2), where T is actually the period.

Now, we know the distance it travels is in a circular motion, so we can assume the distance it travels is equal to the circumference of that circle. Since we know that equation to be d=2Ï€r, we can sub that into our equation to make Fc=(m[2Ï€r]2)/(rT2). Expand that square brackets to make Fc=(m4Ï€2r2)/(rT2). After cancelling one radius from the top and bottom, you are left with the final equation:

Fc=(m4Ï€2r)/T2, where m = the mass of the revolving object, r = radius of the curvature, and T = rotation period of the revolving mass.

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Q: What relationship exists among mass radius of rotation period of revolving mass and the centripetal force in uniform circular motion?
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