The question is one of voltage loss. The goal is to have enough ampacity in the selected conductors to run the maximum load with only 3 percent voltage drop, caused by the resistance inherent in the wires.
Plug your numbers into a voltage drop calculator online and see what pops out.
At 120 volts you would get 3.1 percent drop using 3/0 wire.
At 240 volts you could drop down three sizes to #1 AWG for 3.1 percent at max load, or 1/0 size for 2.5 percent drop at max load.
Assuming copper wire at normal conditions of temperature.
To answer this question the voltage and load amperage is needed.
8 gauge will be sufficient with less than a half volt drop
The main piece of information needed is the load wattage or amperage that will be connected to the power supply. Once this is known the power supply of a greater size that the load should be chosen. Also with this information the size of the wires can be calculated from the power supply to the load. Too small a wire will create a voltage drop at the load end of the circuit. This will cause under performance of the load.
This is a voltage drop question. To answer this question a voltage has to be stated. The higher the voltage to the circuit becomes the smaller the wire size needed. After a certain voltage point the wire size will remain constant and the voltage drop at the load will become smaller.
AWG # 10 wire on 30 amp circuit.
8 gauge will be sufficient with less than a half volt drop
To answer this question the voltage and load amperage is needed.
The size of the generator is based on the size of the load you want to supply. Size up the load in watts or amps along with what phase (single or three) and voltage that the load requires. These are needed to give a complete answer.
The number of pulleys needed to lift a load varies based on the size of the load. A very small load can be lifted with just one pulley while large loads may require many pulleys to adequately lift the load.
The main piece of information needed is the load wattage or amperage that will be connected to the power supply. Once this is known the power supply of a greater size that the load should be chosen. Also with this information the size of the wires can be calculated from the power supply to the load. Too small a wire will create a voltage drop at the load end of the circuit. This will cause under performance of the load.
That question cannot be answered without knowing the load on the beam.
A DLH will work.
38 feet longIt is not possible to give a definite answer without more detail. The construction and type of roof will determine the load (weight) bearing on the beam, and factors such as wind load and earthquake load, and the way the roof bears on the beam (truss/point load/distributed load) will all affect the sizing.
38 feet longIt is not possible to give a definite answer without more detail. The construction and type of roof will determine the load (weight) bearing on the beam, and factors such as wind load and earthquake load, and the way the roof bears on the beam (truss/point load/distributed load) will all affect the sizing.
To answer this question the size of the cable or the amperage of the load is needed to calculate the correct wire size and connectors to fit the cable.
The size of conduit is based on the size of the wires in it. The size of the wires depends on the load connected in the house. Without these other two values an answer can not be given.
Wire size is calculated from the amount of current the load draws. More information is needed. Voltage and amperage will do fine.