This depends on the circuit in question. If the circuit only has resistors and maybe incandescent light bulbs, then with an equvalent RMS voltage of AC, to the previous DC, the circuit will behave almost the same. If the circuit has components such as capacitors and inductors, then the current will be shifted to flow at a waveform which no longer matches the voltage waveform.
If you're talking about a circuit which was designed to run on a 12 volt battery, then you go and plug it into the wall, it will probably break, as the equivalent voltage causes a much higher current than these components were designed to handle.
That would depend on the power supply.
A device or circuit that provides power to the rest of the circuit or system is called a power supply,
the brightness of the bulbs would decrease because the cell would have to supply more power.
Ghost power may be acting on a circuit if it has a capacitor or transformer connected. This will supply power long after the input has been disconnected.
Power supplies don't fail. Idiot.
That would depend on the power supply.
is an embedded circuit or stand alone unit the function of which is to supply a stable voltage to a circuit or device that must be operated within certain power supply limits .
A device or circuit that provides power to the rest of the circuit or system is called a power supply,
That depends what circuit it is in. If it is in a sweep circuit (vertical/horizontal) no because it will change the frequency of the circuit. If it is in a power supply circuit, probably yes becuase it is probable only being used as a filter. BUT if that leg of the power circuit supplies a sweep circuit, no.
because the power still are in circuit of the motherboard and you have to drain the system
Both take current and energy from the power supply and dissipate power.
the brightness of the bulbs would decrease because the cell would have to supply more power.
a power supply (eg: battery) and a load (eg: resistor) even a piece wire shorting two terminals of the power supply is a closed circuit
Well, first of all, if the resistance of the circuit is 10 ohms and you connect 10 volts to it,then the current is 1 Amp, not 2 . So either there's something else in your circuit thatyou're not telling us about, or else the circuit simply doesn't exist.-- If you connect some voltage to some resistance, then the resistance heats up anddissipates (voltage)2/resistancewatts of power, and the power supply has to supply it.-- If there is some current flowing through some resistance, then the resistance heats up anddissipates (current)2 x (resistance)watts of power, and the power supply has to supply it.-- If there's a circuit with some voltage connected to it and some current flowingthrough it, then the resistance of the circuit is (voltage)/(current) ohms, the partsin the circuit heat up and dissipate (voltage) x (current) watts of power, andthe power supply has to supply it.There's no such thing as "the power of a circuit". The power supply supplies thecircuit with some amount of power, the circuit either dissipates or radiates someamount of power, and the two amounts are equal.
Ghost power may be acting on a circuit if it has a capacitor or transformer connected. This will supply power long after the input has been disconnected.
The circuit by itself doesn't determine the voltage of the power supply. If there's some additional requirement that goes along with the circuit, such as "The current through the circuit must be XYZ amperes.", or "The voltage across the third component from the north end of the circuit shall be ABC volts,", then that requirement would dictate the power supply voltage. But in order to calculate it, you'd need the knowledge of every component in the series circuit.
to complete the circuit and back to power supply