It probably wouldn't light up. It might do many other things instead (or despite). It really depends on the circuit in question - maybe it wasn't even designed to have a bulb in it?
I'm sorry, this isn't the place for school assignments, but if you do post them, please - at least provide the bare minimum so that the question can be meaningfuly answered.
Nothing will happen to circuit..... as usual the circuit would be supplying 220v(if india) and certain current...but there is no bulb to consume power...
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
Nothing special should happen. What matters for the bulb is the voltage difference between its ends.
There will no longer be current to heat the filament which will then cool and no longer emit visible light. While it is cooling it will continue to emit infrared light for a time.
If you unscrewed any bulb in the circuit it would turn all of the bulbs off.
it would be ok in a circuit which didn't need a light bulb.
Nothing will happen to circuit..... as usual the circuit would be supplying 220v(if india) and certain current...but there is no bulb to consume power...
Nothing much will happen except the same bulb will not blow..
In a series circuit, if another bulb is added, it is going to dim.
The function of a light bulb in an electric circuit is that it turns electrical energy into light.
it look's like a mini light bulb and you usally use them in an electric circuit
If you connect the circuit properly the bulb should light up. That means attaching the left side of the battery to the right side of the bulb using a wire and attaching the right side of the battery to the left side of the bulb. If you do that the your bulb should turn on. If it doesn't then try changing the battery or the bulb.
There are many. One example would be an item used in an electric circuit, like a bulb.
The glass of the light bulb is not conductive, so the circuit would not be completed. You would need to join the wires to the positive and negative contacts on the base of the bulb for the circuit to work.
If the bulb's filament is broken, the whole circuit becomes open. If the bulb is in a series circuit or is the only bulb, the electricity would no longer flow. If the bulb is in a parallel circuit, along with other bulbs, then only the blown bulb would go out, and the other bulbs would still work.
For parallel circuit, there's bronchus which mean the electric current'd have to choose which path to go. There's a main loop and more than one bronchus.If the bulb in one of the bronchus break down,the other bulbs would still light up. For series circuit,there's only one path for the electric current to flow through.If one of the bulb breaks down,the other'd go out as well. The electric current of evbery bulb in a series circuit is the same while the electric current of bulb in parallel circuit are not the same. The sum of the bronchus in a parallel circuit is equal to the main loop's.The more bulbs in a path,the more resistance will there be and less brighter it will be.A larger current will flow through the path with lower resistance so te brightness of the bulb of the bronchus will hace differences asc well.
You need a Battery, Light Bulb, Ammeter, Switch.